Draw the product of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry where appropriate. Ignore inorganic byproducts. НО KMNO4 Select to Draw
Draw the product of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry where appropriate. Ignore inorganic byproducts. НО KMNO4 Select to Draw
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Instructions:**
Draw the product of the reaction shown below. Use wedge and dash bonds to indicate stereochemistry where appropriate. Ignore inorganic byproducts.
**Reaction Details:**
The starting compound is a branched alcohol. It features a hydroxyl group (OH) attached to a carbon chain that has both an upward and a horizontal branching.
**Reagent Involved:**
- **KMnO₄:** Potassium permanganate is the reagent used in this oxidation reaction.
**Product Drawing:**
Make use of the "Select to Draw" area to sketch the structure of the product, ensuring to highlight stereochemistry using wedge and dash bonds if needed.

Transcribed Image Text:**Ranking Carboxylic Acids by pKa**
**Objective:**
Rank the given carboxylic acids from lowest to highest pKa. Remember, a lower pKa indicates a more acidic compound.
**Compounds to Rank:**
1. **Compound 1:** Contains a bromine (Br) atom attached to the second carbon from the carboxyl group.
2. **Compound 2:** Features a bromine (Br) atom at the third carbon from the carboxyl group.
3. **Compound 3:** Has a bromine (Br) atom on the fourth carbon from the carboxyl group.
4. **Compound 4:** Contains a bromine (Br) on the third carbon, but a different chain structure from Compound 2.
**Ranking Options:**
A) 1 < 2 < 3 < 4
B) 4 < 3 < 2 < 1
C) 4 < 1 < 3 < 2
D) 1 < 3 < 2 < 4
E) 2 < 3 < 4 < 1
**Explanation:**
- The acidity of carboxylic acids is influenced by the presence of electronegative substituents like bromine (Br).
- Bromine is an electron-withdrawing group that stabilizes the carboxylate ion, making the acid more acidic.
- The closer the bromine is to the carboxyl group, the more acidic the compound due to a greater inductive effect.
**Conclusion:**
Analyze the position of the bromine in each compound relative to the carboxyl group to determine the correct ranking from lowest to highest pKa.
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