Draw the organic product expected from the reaction. Include all hydrogen atoms. Note that K,Cr,0, is present in excess. Select Draw Rings More Erase H, SO, CH,CH, CH, OH + K,Cr,O,(aq)

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**Instructions for Drawing Organic Product:**

Title: Drawing the Organic Product from an Oxidation Reaction

**Objective:**
Draw the expected organic product from the given reaction. Ensure all hydrogen atoms are included.

**Reaction Details:**

- **Reactants:**  
  - Propanol: \( \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} \)
  - Potassium Dichromate (in excess): \( \text{K}_2\text{Cr}_2\text{O}_7 \) (aqueous)
  - Sulfuric Acid: \( \text{H}_2\text{SO}_4 \)

- **Reaction Type:** Oxidation of alcohol to carboxylic acid.
  
- **Expected Organic Product:** The alcohol (\( \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} \)) will be oxidized to form propanoic acid (\( \text{CH}_3\text{CH}_2\text{COOH} \)).

**Tools Available:**

- **Select**: Choose specific atoms or bonds.
- **Draw**: Create and modify structures.
- **Rings**: Add ring structures if needed.
- **More**: Additional drawing tools.
- **Erase**: Remove unwanted parts.
- **Undo/Redo**: Adjust previous actions.
- **Zoom In/Out**: Focus on specific areas of the drawing.

**Instructions:**

1. Start by identifying the structure of the initial reactant, propanol (\( \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} \)).
2. Apply the oxidation process with \( \text{K}_2\text{Cr}_2\text{O}_7 \) in acidic conditions to convert the alcohol functional group to a carboxylic acid group (\( -\text{COOH} \)).
3. Draw the resulting propanoic acid. Ensure all hydrogen atoms are displayed in the structure.

This is a classic example of a primary alcohol being oxidized to a carboxylic acid using a strong oxidizing agent like potassium dichromate in an acidic medium. Adjust your drawing tools to accurately represent each atom and bond in the product structure.
Transcribed Image Text:**Instructions for Drawing Organic Product:** Title: Drawing the Organic Product from an Oxidation Reaction **Objective:** Draw the expected organic product from the given reaction. Ensure all hydrogen atoms are included. **Reaction Details:** - **Reactants:** - Propanol: \( \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} \) - Potassium Dichromate (in excess): \( \text{K}_2\text{Cr}_2\text{O}_7 \) (aqueous) - Sulfuric Acid: \( \text{H}_2\text{SO}_4 \) - **Reaction Type:** Oxidation of alcohol to carboxylic acid. - **Expected Organic Product:** The alcohol (\( \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} \)) will be oxidized to form propanoic acid (\( \text{CH}_3\text{CH}_2\text{COOH} \)). **Tools Available:** - **Select**: Choose specific atoms or bonds. - **Draw**: Create and modify structures. - **Rings**: Add ring structures if needed. - **More**: Additional drawing tools. - **Erase**: Remove unwanted parts. - **Undo/Redo**: Adjust previous actions. - **Zoom In/Out**: Focus on specific areas of the drawing. **Instructions:** 1. Start by identifying the structure of the initial reactant, propanol (\( \text{CH}_3\text{CH}_2\text{CH}_2\text{OH} \)). 2. Apply the oxidation process with \( \text{K}_2\text{Cr}_2\text{O}_7 \) in acidic conditions to convert the alcohol functional group to a carboxylic acid group (\( -\text{COOH} \)). 3. Draw the resulting propanoic acid. Ensure all hydrogen atoms are displayed in the structure. This is a classic example of a primary alcohol being oxidized to a carboxylic acid using a strong oxidizing agent like potassium dichromate in an acidic medium. Adjust your drawing tools to accurately represent each atom and bond in the product structure.
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