Draw the Norton equivalent for the circuit given. For the Short circuit current (with respect to terminal ab): Isc = mA a 15k2 10mA 10k2 = 30V 3mA 5kQ

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Draw the Norton equivalent for the circuit given.
For the Short circuit current (with respect to terminal ab):
Isc =
mA
a
15k2
10mA
– 30V
3mA
5kQ
b
Transcribed Image Text:Draw the Norton equivalent for the circuit given. For the Short circuit current (with respect to terminal ab): Isc = mA a 15k2 10mA – 30V 3mA 5kQ b
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