Draw the major product(s) of the following reactions, if there is a reaction. Be sure to include stereochemistry in your products. CEN H30* 32 NaOH но он H. H30*

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**Transcription for Educational Website**

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**Instructions:**

Draw the **major product(s)** of the following reactions, if there is a reaction. **Be sure to include stereochemistry in your products.**

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**Reactions:**

1. Cyclopentanecarbonitrile (a five-membered ring with a cyanide group) reacting with \( \text{H}_3\text{O}^+ \). 

2. Methyl ketone with a benzene ring on one side reacts with \( 3 \, \text{I}_2 \) / \( \text{NaOH} \). 

3. Propanal (a three-carbon aldehyde) with ethylene glycol in the presence of \( \text{H}_3\text{O}^+ \).

4. Cyclohexanone reacts in two steps:
   - Step 1: \( \text{LDA} \), \( \text{THF} \)
   - Step 2: 2-methylpropanal (a four-carbon aldehyde with a methyl group on the second carbon).

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**Explanation of Diagrams and Reactions:**

- **Diagram 1:** The structure shows a cyclopentane ring with a nitrile group (\(-C \equiv N\)). When hydrolyzed with \( \text{H}_3\text{O}^+ \), it will likely result in a carboxylic acid.

- **Diagram 2:** The compound is a phenyl methyl ketone. The reaction conditions suggest iodination under basic conditions, likely leading to the formation of iodoform and a carboxylate ion.

- **Diagram 3:** Shows aldehyde protection as an acetal. Propanal reacts with ethylene glycol in acidic conditions leading to the formation of a cyclic acetal.

- **Diagram 4:** This is an enolate formation followed by an aldol reaction. Cyclohexanone forms its enolate with LDA, then reacts with 2-methylpropanal to form a β-hydroxy ketone. 

**Note:** For all reactions, consider any possible stereochemical outcomes and depict them in your structural representations.
Transcribed Image Text:**Transcription for Educational Website** --- **Instructions:** Draw the **major product(s)** of the following reactions, if there is a reaction. **Be sure to include stereochemistry in your products.** --- **Reactions:** 1. Cyclopentanecarbonitrile (a five-membered ring with a cyanide group) reacting with \( \text{H}_3\text{O}^+ \). 2. Methyl ketone with a benzene ring on one side reacts with \( 3 \, \text{I}_2 \) / \( \text{NaOH} \). 3. Propanal (a three-carbon aldehyde) with ethylene glycol in the presence of \( \text{H}_3\text{O}^+ \). 4. Cyclohexanone reacts in two steps: - Step 1: \( \text{LDA} \), \( \text{THF} \) - Step 2: 2-methylpropanal (a four-carbon aldehyde with a methyl group on the second carbon). --- **Explanation of Diagrams and Reactions:** - **Diagram 1:** The structure shows a cyclopentane ring with a nitrile group (\(-C \equiv N\)). When hydrolyzed with \( \text{H}_3\text{O}^+ \), it will likely result in a carboxylic acid. - **Diagram 2:** The compound is a phenyl methyl ketone. The reaction conditions suggest iodination under basic conditions, likely leading to the formation of iodoform and a carboxylate ion. - **Diagram 3:** Shows aldehyde protection as an acetal. Propanal reacts with ethylene glycol in acidic conditions leading to the formation of a cyclic acetal. - **Diagram 4:** This is an enolate formation followed by an aldol reaction. Cyclohexanone forms its enolate with LDA, then reacts with 2-methylpropanal to form a β-hydroxy ketone. **Note:** For all reactions, consider any possible stereochemical outcomes and depict them in your structural representations.
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