**Transcription for Educational Website**---**Instruction:**Draw the major product of this reaction. Ignore inorganic byproducts.**Chemical Reaction:**- **Reactant:** The image depicts a chemical structure with a linear zigzag or zig-zag line representing a carbon chain. There is a triple bond at one end of the chain, indicating an alkyne group.- **Reagent:** HBr (excess)**Reaction Arrow:** An arrow pointing downwards from the chemical structure signifies the progression of the reaction with HBr in excess.**Product Box:** Below the arrow is a dashed red rectangle labeled "Drawing" where the major product of the reaction is expected to be drawn. **Diagram Explanation:**- The reactant is likely an alkyne due to the presence of a triple bond. - The presence of excess HBr implies that the alkyne will undergo hydrohalogenation, potentially forming a haloalkane through Markovnikov’s rule.- The task is to draw the major product formed from this reaction, taking into account the principle of regioselectivity and ignoring any inorganic byproducts. **Note to Learners:**Consider how the excess HBr will react with the triple bond when predicting the structure of the major organic product.

An arrow always depicts from a region of high electron density to low electron density ; that is tail depicts region of high electron density and head depicts region of low electron density.This is an electrophilic addition reaction.In first step, electrophilic attack of bromine takes place across triple bond to form bromonium ion.Next, bromide nucleophile attacks to form anti-dibromide product.In similar manner, another equivalent of hydrogen bromide adds across double bond to form dibromide product.