Draw the major product of this reaction. Ignore inorganic byproducts and the alkoxide side product. or N H 1. excess LIAIH4 2. H₂O

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Chapter1: Chemical Foundations
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**Instruction:**

Draw the major product of the reaction. Ignore inorganic byproducts and the alkoxide side product.

**Reaction Details:**

1. **Starting Compound:** A cyclic amide structure is provided, specifically, a caprolactam. The molecule consists of a 6-membered ring with an amide linkage (C=O connected to NH).

2. **Reagents:**
   - Step 1: Excess LiAlH₄ (Lithium aluminum hydride)
   - Step 2: H₂O (Water)

**Reaction Pathway:**

LiAlH₄ is a strong reducing agent typically used to reduce amides to amines. When a cyclic lactam like caprolactam is treated with LiAlH₄, it is expected to reduce the amide group to a secondary amine without breaking the ring structure.

**Outcome:**

The reaction should convert the amide group (C=O) to a methylene (CH₂) linked to nitrogen, resulting in a ring with a secondary amine.

**Drawing:**

A placeholder is provided indicating where the drawing of the product should go.
Transcribed Image Text:**Instruction:** Draw the major product of the reaction. Ignore inorganic byproducts and the alkoxide side product. **Reaction Details:** 1. **Starting Compound:** A cyclic amide structure is provided, specifically, a caprolactam. The molecule consists of a 6-membered ring with an amide linkage (C=O connected to NH). 2. **Reagents:** - Step 1: Excess LiAlH₄ (Lithium aluminum hydride) - Step 2: H₂O (Water) **Reaction Pathway:** LiAlH₄ is a strong reducing agent typically used to reduce amides to amines. When a cyclic lactam like caprolactam is treated with LiAlH₄, it is expected to reduce the amide group to a secondary amine without breaking the ring structure. **Outcome:** The reaction should convert the amide group (C=O) to a methylene (CH₂) linked to nitrogen, resulting in a ring with a secondary amine. **Drawing:** A placeholder is provided indicating where the drawing of the product should go.
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