Draw the major product of the Claisen condensation reaction between two molecules of this ester. Ignore inorganic byproducts. O 1. NaOCH 3/ CH3OH 2. Acidic workup

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### Claisen Condensation Reaction

**Objective:**  
Draw the major product of the Claisen condensation reaction between two molecules of this ester. Ignore inorganic byproducts.

**Starting Material:**  
The structure of the ester is provided, featuring a carbonyl group (C=O) with an ethyl group (–CH₂CH₃) and a methoxy group (–OCH₃) attached on either side of the carbonyl carbon.

**Reaction Conditions:**

1. **Reagents:**
   - Sodium methoxide (NaOCH₃) in methanol (CH₃OH)
   - Followed by an acidic workup

**Diagram Explanation:**

- A skeletal formula of an ester is shown with the following components:
  - A two-carbon chain attached to the carbonyl group.
  - The carbonyl carbon is bonded to an oxygen which is further bonded to a methyl group (methoxy group).

- The arrow indicates that this ester undergoes a reaction under the given conditions.

- The reaction conditions are outlined next to the arrow, specifying the use of a base (NaOCH₃ in CH₃OH) and an acidic workup.

**Expected Outcome:**

The Claisen condensation involves the base-catalyzed formation of a β-keto ester by the condensation of two ester molecules. After the removal of an α-hydrogen and subsequent nucleophilic acyl substitution, the deprotonation and acid workup will yield the final product. The ester in question will react with itself, leading to the formation of a new carbon-carbon bond. 

The structure of the product is not shown, and users are encouraged to visualize or draw the expected β-keto ester product formed as a result of this reaction.
Transcribed Image Text:### Claisen Condensation Reaction **Objective:** Draw the major product of the Claisen condensation reaction between two molecules of this ester. Ignore inorganic byproducts. **Starting Material:** The structure of the ester is provided, featuring a carbonyl group (C=O) with an ethyl group (–CH₂CH₃) and a methoxy group (–OCH₃) attached on either side of the carbonyl carbon. **Reaction Conditions:** 1. **Reagents:** - Sodium methoxide (NaOCH₃) in methanol (CH₃OH) - Followed by an acidic workup **Diagram Explanation:** - A skeletal formula of an ester is shown with the following components: - A two-carbon chain attached to the carbonyl group. - The carbonyl carbon is bonded to an oxygen which is further bonded to a methyl group (methoxy group). - The arrow indicates that this ester undergoes a reaction under the given conditions. - The reaction conditions are outlined next to the arrow, specifying the use of a base (NaOCH₃ in CH₃OH) and an acidic workup. **Expected Outcome:** The Claisen condensation involves the base-catalyzed formation of a β-keto ester by the condensation of two ester molecules. After the removal of an α-hydrogen and subsequent nucleophilic acyl substitution, the deprotonation and acid workup will yield the final product. The ester in question will react with itself, leading to the formation of a new carbon-carbon bond. The structure of the product is not shown, and users are encouraged to visualize or draw the expected β-keto ester product formed as a result of this reaction.
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