Draw the major organic product for the reaction shown. 1. PPH3 2. BuLi Br 3.

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Question 7

**Title: Understanding the Major Organic Product in a Reaction**

**Objective:**
To identify the major organic product in the given chemical reaction sequence.

**Reaction Overview:**
We are starting with a bromobenzene derivative and using phosphorus triphenyl (PPh₃) and butyllithium (BuLi) as reagents. These will facilitate a reaction that involves a carbonyl compound with a ketone function.

**Reagents and Conditions:**

1. **PPh₃ (Triphenylphosphine):** This reagent is typically used to form Wittig reagents, which are ylides, by reaction with alkyl halides.
   
2. **BuLi (Butyl Lithium):** A strong base that can remove protons and initiate nucleophilic additions.

3. **Carbonyl Compound:** In this case, it is a ketone, signified by the C=O moiety present in the diagram.

**Reaction Steps:**

1. **Formation of the Ylide:** The bromide from the benzene derivative will react with PPh₃ to form a phosphonium salt. 
   
2. **Deprotonation:** BuLi will deprotonate the phosphonium salt, forming the ylide.

3. **Wittig Reaction:** The ylide will then react with the ketone. This reaction is known for converting carbonyl groups to alkenes.

**Expected Outcome:**
The product of this reaction is typically an alkene, formed by replacing the C=O group with a C=C bond linking the two original fragments (the benzene derivative and the ketone).

**Conclusion:**
This reaction exemplifies the Wittig reaction, an essential tool in organic chemistry for constructing carbon-carbon double bonds by reacting phosphonium ylides with carbonyl compounds. This process is valuable in synthetic organic chemistry, facilitating the formation of various complex organic molecules.
Transcribed Image Text:**Title: Understanding the Major Organic Product in a Reaction** **Objective:** To identify the major organic product in the given chemical reaction sequence. **Reaction Overview:** We are starting with a bromobenzene derivative and using phosphorus triphenyl (PPh₃) and butyllithium (BuLi) as reagents. These will facilitate a reaction that involves a carbonyl compound with a ketone function. **Reagents and Conditions:** 1. **PPh₃ (Triphenylphosphine):** This reagent is typically used to form Wittig reagents, which are ylides, by reaction with alkyl halides. 2. **BuLi (Butyl Lithium):** A strong base that can remove protons and initiate nucleophilic additions. 3. **Carbonyl Compound:** In this case, it is a ketone, signified by the C=O moiety present in the diagram. **Reaction Steps:** 1. **Formation of the Ylide:** The bromide from the benzene derivative will react with PPh₃ to form a phosphonium salt. 2. **Deprotonation:** BuLi will deprotonate the phosphonium salt, forming the ylide. 3. **Wittig Reaction:** The ylide will then react with the ketone. This reaction is known for converting carbonyl groups to alkenes. **Expected Outcome:** The product of this reaction is typically an alkene, formed by replacing the C=O group with a C=C bond linking the two original fragments (the benzene derivative and the ketone). **Conclusion:** This reaction exemplifies the Wittig reaction, an essential tool in organic chemistry for constructing carbon-carbon double bonds by reacting phosphonium ylides with carbonyl compounds. This process is valuable in synthetic organic chemistry, facilitating the formation of various complex organic molecules.
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