Draw the Lewis structure of C2H4CI2 (both CI atoms on one C atom) and then determine if the molecule is polar or nonpolar.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter2: Atoms, Molecules, And Ions
Section: Chapter Questions
Problem 2.103QE
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**Question: Lewis Structure and Polarity of C2H4Cl2**

- **Task**: Draw the Lewis structure of C₂H₄Cl₂ (both chlorine atoms attached to one carbon atom) and determine if the molecule is polar or nonpolar.

**Explanation**:
1. **Lewis Structure**:
   - Identify the total number of valence electrons: Carbon (C) has 4 each, Hydrogen (H) has 1 each, and Chlorine (Cl) has 7 each. Total: 2(4) + 4(1) + 2(7) = 24 electrons.
   - Draw a central carbon atom bonded to two hydrogens and the other carbon, which is bonded to two chlorines.
   - Complete the octets for carbon and chlorine atoms.

2. **Polarity**:
   - Determine the shape of the molecule.
   - Analyze the distribution of electron density.
   - A molecule with symmetrical charge distribution is nonpolar, while one with an asymmetrical distribution is polar.
Transcribed Image Text:**Question: Lewis Structure and Polarity of C2H4Cl2** - **Task**: Draw the Lewis structure of C₂H₄Cl₂ (both chlorine atoms attached to one carbon atom) and determine if the molecule is polar or nonpolar. **Explanation**: 1. **Lewis Structure**: - Identify the total number of valence electrons: Carbon (C) has 4 each, Hydrogen (H) has 1 each, and Chlorine (Cl) has 7 each. Total: 2(4) + 4(1) + 2(7) = 24 electrons. - Draw a central carbon atom bonded to two hydrogens and the other carbon, which is bonded to two chlorines. - Complete the octets for carbon and chlorine atoms. 2. **Polarity**: - Determine the shape of the molecule. - Analyze the distribution of electron density. - A molecule with symmetrical charge distribution is nonpolar, while one with an asymmetrical distribution is polar.
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