Draw the Gantt Chart for the following task given in the table using:• Short Job First Non-preemptive• Short Job First Preemptive• Round robin (quantum =4)Computation ArrivalProcessTimeTimeP1150P2123P342

Shortest Job First (SJF):In this, the jobs are executed at the CPU according to computational time.…

Answered: Draw the Gantt Chart for the following…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Table 1. 4 processes arriving shown in Operating System Scheduling PDF for Shortest Job Next, non- preemptive Process Arrival Times Execution Times Service Times sequence Wait Times calculations PO 0 12 P1 21 9 P2 41 6 P3 6 3 Total wait time = ? Here the 4 processes of the PDF are repeated in Table 1, with arrival times changed to 0, 2, 4, and 6 respectively. Also, the execution times are changed to 12, 9, 6, and 3. You will be asked to fill table 1 with the numbers like the service times (when is each process serviced), the sequence of executions of these 4 processes in part (a) and part (b) below. Also, you will compute the total wait time. Note for FCFS, it is 1, 2, 3, 4 for P0, P1, P2, and P3; • for the SJN or Shortest Job Next with non-preemptive, PO is #1, P1 may not be #2; for SRT, or shortest remaining time, the preemptive version of SJN, PO is #1, but after 2 time units when P1 comes, P1 kicks out PO since its execution time is 4 < 9- 2 = 7; and P1 may be preempted by P2 later…
Consider the following task set. Task T T1 1 3 T2 2 4 T3 1 6 Using a timeline, show how a cyclic executive can be constructed for the task set. You may assume that the tasks can be arbitrarily “split up", but only at integer execution-time points. Thus, cach split-part of a task will have an integer execution time.
Consider the task set in Table 1. a) Assume one of the tasks in Table 1 has its deadline reduced by 1. Now, what is the most efficient schedulability test for determining whether the task set in Table 1 is schedulable under preemptive RM?
Given the following jobs/processes, job lengths, and arrival times, compute the completion time,turnaround time, and waiting time for each job in a table. Draw the Gantt chart and suggest anapplication for each job. (Consider 5 as a highest priority and 0 as a lowest priority).a. First Come First Serve (FCFS)b. Shortest Job First Scheduling (SJF) algorithm.c. Shortest Remaining time (SRT) algorithm.BN104 Operating System 4Prepared by: Archana Banepali Moderated by: Dr Rajan Kadel T1, 2023Question 4d. Non-preemptive priority scheduling algorithme. Pre-emptive priority Scheduling algorithmf. Round-Robin Scheduling algorithm (consider time slice is 4ms).Process Burst Time ArrivalTimePriorityP1 11 2 3P2 28 1 1P3 2 3 4P4 10 4 2P5 16 5 5Table: Processes with Arrival Time, Burst Time and Priority
1. Solve the following processes in table, by using Shortest Job First (non-preemptive method) and calculate average waiting time. Process Burst Time P1 P2 P3 P4 P5 5 4 8 9 3

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Draw the Gantt Chart for the following task given in the table using: • Short Job First Non-preemptive • Short Job First Preemptive • Round robin (quantum =4) Computation Arrival Process Time Time P1 15 0 P2 12 3 P3 4 2