Draw the chair conformation as well as flipped chair for the structure below and determine which one is more stable and why? Calculate the energy cost with respect to 1,3-diaxial interactions for each structure using the table below. Table of 1,3-diaxaial interaction costs (taken from Table 4.8 in e-text) One 1,3-diaxial interaction Energy Cost (KJ/mol) H and H 0 H and Cl 1.0 H and OH 2.1 H and CH3 3.8 H and CH₂CH3 4.0 H and CH (CH3)2 4.6 11.4 H and C(CH3)3 CH3 and CH3 9.2

Draw the chair conformation as well as flipped chair for the structure below and determine which one is more stable and why? Calculate the energy cost with respect to 1,3-diaxial interactions for each structure using the table below. Table of 1,3-diaxaial interaction costs (taken from Table 4.8 in e-text) One 1,3-diaxial interaction Energy Cost (KJ/mol) H and H 0 H and Cl 1.0 H and OH 2.1 H and CH3 3.8 H and CH₂CH3 4.0 H and CH (CH3)2 4.6 11.4 H and C(CH3)3 CH3 and CH3 9.2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question 2. Fill in the substituents (including hydrogens) for the chair conformation of the molecule below. Draw all your substituents relative to the carbon with the green asterisk (*). OH OH A C B E # F K H L
Draw the structure of the following molecules that result from the flipping of the existing chair conformation. See attached structures:
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Consider the following compound: *figure is screenshot* Draw the flipped structure and calculate the total energy cost associated with each conformation(both the structure above and its flipped conformation)using the following information: CH3-H 1,3-diaxial= 3.8 KJ/mol; Assume there is no cost of energy when a CH3group is at the equatorial position.
Draw the two possible chair conformations for the below molecule. Clearly indicate whether the substituents are axial (a) or equatorial (e).
a. Use strain energy increments in the OWL Table Reference (see References button, Strain Energy Increments) to calculate the energy difference between the two chair conformations of the compound b. Specify substituent positions (axial or equatorial) in the more stable chair. c. Estimate the percent of the more stable chair at equilibrium at 25°C. (To determine the percent of the more stable chair at equilibrium, first calculate Keq, and then use this value to find the percentage.) CH3 CH3 Answers: a. The energy difference is b. In the more stable chair: • The phenyl group is in the • The isopropyl group is in the | kJ/mol. position. position. c. At 25°C the equilibrium percent of the more stable chair conformation is approximately [
Compare the two possible chair conformations of this molecule. Given the AG for the two possible chair conformations, calculate the equilibrium constant for the interconversion between the two chair conformers at room temperature. CI H3C AG = 1.3 kcal/mol %3D AG = -RT In K %3D rearranges to K = e-AG/RT %3D R = 1.987 x 10-3 kcal/molK ||
5. Draw the most stable chair conformer of the compound shown below Il..
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