Draw the beta-pyranose structure of the following straight-chan sugar then list the TOP species in order of carbon 1-5 and select the matching answer. A) 1- OH | 2 - H|3- OH |4 - OH | 5 - CH:OH HO B) 1- OH | 2 - OH |3- OH | 4 -H|5 - CH:OH но H- C) 1- H|2- OH |3- OH |4 - H|5 - CH:OH H- OH D) 1- OH | 2 - OH |3- OH | 4 - H|5 - H H- -O- E) 1 -H|2-H|3 - H | 4 - OH | 5-H CH,OH

Introductory Chemistry: An Active Learning Approach
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Chapter22: Biochemistry
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**Question 13 of 24**

**Activity: Understanding Sugar Structures**

**Task:** Draw the beta-pyranose structure of the given straight-chain sugar. Then list the substituents (TOP species) in order of carbons 1-5 and select the matching answer.

**Straight-Chain Sugar Diagram Explanation:**
The diagram shows a vertical linear projection of a sugar molecule. It consists of:

- Top: A double-bonded oxygen (O) with a hydrogen (H) attached at carbon 1.
- Down the chain: A series of hydroxyl (OH) groups and hydrogen atoms attached to carbons 2 through 5.
- Bottom: A CH₂OH group is attached to the last carbon.

**Choices:**
- A) 1 - OH | 2 - H | 3 - OH | 4 - OH | 5 - CH₂OH
- B) 1 - OH | 2 - OH | 3 - H | 4 - H | 5 - CH₂OH
- C) 1 - H | 2 - OH | 3 - OH | 4 - H | 5 - CH₂OH
- D) 1 - OH | 2 - OH | 3 - OH | 4 - H | 5 - H
- E) 1 - H | 2 - H | 3 - H | 4 - OH | 5 - H

**Instructions:**
1. Convert the linear structure to a cyclic beta-pyranose form.
2. List the apical substituents at carbons 1 to 5 in the pyranose form.
3. Choose the correct sequence from the options given above based on your listing.
Transcribed Image Text:**Question 13 of 24** **Activity: Understanding Sugar Structures** **Task:** Draw the beta-pyranose structure of the given straight-chain sugar. Then list the substituents (TOP species) in order of carbons 1-5 and select the matching answer. **Straight-Chain Sugar Diagram Explanation:** The diagram shows a vertical linear projection of a sugar molecule. It consists of: - Top: A double-bonded oxygen (O) with a hydrogen (H) attached at carbon 1. - Down the chain: A series of hydroxyl (OH) groups and hydrogen atoms attached to carbons 2 through 5. - Bottom: A CH₂OH group is attached to the last carbon. **Choices:** - A) 1 - OH | 2 - H | 3 - OH | 4 - OH | 5 - CH₂OH - B) 1 - OH | 2 - OH | 3 - H | 4 - H | 5 - CH₂OH - C) 1 - H | 2 - OH | 3 - OH | 4 - H | 5 - CH₂OH - D) 1 - OH | 2 - OH | 3 - OH | 4 - H | 5 - H - E) 1 - H | 2 - H | 3 - H | 4 - OH | 5 - H **Instructions:** 1. Convert the linear structure to a cyclic beta-pyranose form. 2. List the apical substituents at carbons 1 to 5 in the pyranose form. 3. Choose the correct sequence from the options given above based on your listing.
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