Draw out the Lewis structures for H₂CO3, HCO3, and CO32. Then determine the maximum number equivalent resonance structures for each species. Note that carbon is the central atom in all three cases. If the molecule contains hydrogen atoms they are attached to oxygen atoms. Only count the best structures. For example, A structure with really bad formal charges should not be counted. equivalent Lewis structures. equivalent Lewis structures. equivalent Lewis structures. The molecule H₂CO3 has The molecule HCO3 has The molecule CO₂²* has |

Draw out the Lewis structures for H₂CO3, HCO3, and CO32. Then determine the maximum number equivalent resonance structures for each species. Note that carbon is the central atom in all three cases. If the molecule contains hydrogen atoms they are attached to oxygen atoms. Only count the best structures. For example, A structure with really bad formal charges should not be counted. equivalent Lewis structures. equivalent Lewis structures. equivalent Lewis structures. The molecule H₂CO3 has The molecule HCO3 has The molecule CO₂²* has |

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The formal charge is the "charge" an element would have in a molecule or ion if all of the bonding electrons were shared equally between atoms. We can draw three inequivalent Lewis structures for the arsenite ion , AsO33- . The concepts of formal charge and electronegativity can help us choose the structure that is the best representation.1. Assign formal charges to the elements in each of the structures below.Note: Count oxygen atoms starting from the left for each structure.
2. Draw the lewis structures for both resonance structures of the OCBr+ ion and select the statement that is true a. The molecule sometimes looks like one resonances structure, and at other times it looks like the other resonance structure b. In one resonance structure, the carbon is in the center, and in the other one, the oxygen is in the center c. The bond between carbon and oxygen would best be described as 2.5 bonds (halfway between a double and a triple bond) d. In one resonance structure the positive charge is on the bromine, and in the other, it is on the carbon.
An incomplete Lewis structure is shown below. The structure only shows the atoms and how they are connected. The molecule has a net charge of zero. H Н—N—С- -о—с—Н H H Complete the Lewis structure giving all atoms full octets. If there is more than one way to do this, draw resonance structures showing all possibilities. If not, just draw one Lewis structure. Be sure to write in any non-zero formal charges. Click and drag to start drawing a structure.
Xenon is a noble gas that is capable of forming compounds. One of these compounds is XeBr₂Cl₂. XeBr₂Cl₂ has 36 total valence electrons. Draw the correct Lewis structure for XeBr₂Cl₂ that minimizes the formal charges on all atoms.
An incomplete Lewis structure is shown below. The structure only shows the atoms and how they are connected. The molecule has a net charge of zero. H. Br-C-C-N Complete the Lewis structure giving all atoms full octets. If there is more than one way to do this, draw resonance structures showing all possibilities. If not, just draw one Lewis structure. Be sure to write in any non-zero formal charges. Click and drag to start drawing a structure. 回 E
10. Molecule: CzHj0 Indicate the number of available electrons that are in the molecule. ae = Trial Structure: in the space to the right connect all of the atoms to the central atoms (all Cs in a chain) and then make each atom follow the octet rule (duet rule for hydrogen). How many electrons are necessary in the trial structure? ne = Circle the correct ne = ae ne ae relationship between ne and ae. Draw the corrected Lewis Structure to the right. Add Later: e- geometry: molecular geom: Hybridization:
Using only single bonds, draw two corect Lewis structures of HCIO, one with Cl as the central atom and the other with O as the central atom. Calculate the formal charges of all atoms in each molecule. State which is the more likely structure based on the formal charges. In the previous problem, you drew two structures of HCIO. Are these resonance structures? Explain why or why not.
a) Below is a lewis structure of CSO. Draw two resonance structures of this molecule. Assign any formal charges if necessary. b) Now look at your structures. Do they represent equivalent or nonequivalent resonance structures of the original? Why or why not? c) Of all three structures, which contributes the most to the overall resonance hybrid and why? Rank the other two in terms of their contribution
An incomplete Lewis structure is shown. The structure only shows the atom and how they are connected. The molecule has a bet charge of -1. Complete the Lewis structure giving all atoms full octets. If there is more than one way to do this, draw resonance structure showing all possibilities. If not, just draw one Lewis structure. Be sure to write in any non-Zero formal charges..
Assign the formal charges of the “heavy” atoms (non-hydrogen atoms, so in this case C’s, N, O and P) in the Lewis structure below. Note that you should not add or erase the lone pairs
Decide whether these proposed Lewis structures are reasonable. proposed Lewis structure |N—N=N] : 0: :0-C H .. I :Ö: H 1 O-H + Is the proposed Lewis structure reasonable? Yes. No, it has the wrong number of valence electrons. The correct number is: No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are: Yes. No, it has the wrong number of valence electrons. The correct number is: No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are: * Yes. No, it has the wrong number of valence electrons. The correct number is: No, it has the right number of valence electrons but doesn't satisfy the octet rule. The symbols of the problem atoms are: * * If two or more atoms of the same element don't satisfy the octet rule, just enter the chemical symbol as many times as necessary. For example, if two oxygen atoms don't satisfy the octet rule, enter "0,0".
Write a Lewis structure for each of the following polyatomic ions. Show all bonding valenceelectron pairs as lines and all nonbonding valence electron pairs as dots. For those ions thatexhibit resonance, draw the various possible resonance forms.a. phosphate ion, PO4 3-b. chlorate ion, ClO3-