Can I get some help with this two-part problem?Draw a structural formula for each of the substitution products of the reactions shown below. A good explanation but a clear answer would be very much appreciated :) Draw a structural formula for the substitution product of the reaction shown below.BrCH3CH2OHCH3• Use the wedge/hash bond tools to indicate stereochemistry where it exists.If more than one stereoisomer of product is formed, draw both.• Separate multiple products using the + sign from the drop-down menu.Copyaste[FChemDoodleCO [Review Topics][References]Draw a structural formula for the substitution product of the reaction shown below.Naacetone-CH3H.• Use the wedge/hash bond tools to indicate stereochemistry where it exists.If more than one stereoisomer of product is formed, draw both.Separate multiple products using the + sign from the drop-down menu.• Products that are initially formed as ions should be drawn in their neutral forms.C Popyaste6941%

In the given reactions nucleophilic substitution happens. If there are more than one leaving group in the given compound the one with more leaving capacity will leave first.1) Alcohols are polar protic solvents. Some solvents are capable of acting as a nucleophile. Here the given alcohol acts as solvent as well as nucleophile. We have two leaving groups one is bromine and the other one is fluorine. Leaving group ability is more for bromine. So during reaction bromine will undergo substitution. The secondary alkyl halides in polar protic solvent will promote SN1 reaction. That means reaction will proceed through carbocation formation. Mechanism of this reaction is as follows. That means configuration is retained.2) Strong nucleophiles in a polar aprotic solvent favor SN2 mechanism. That means the reaction will occur in a single step. In other words we can say the nucleophile attack and the removal of leaving group take place in the same step. Mechanism of this reaction is as follows. That means inversion in configuration occurs.