Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can someone show the movement of atoms when finding the product?
Transcribed Image Text:**Title: Synthesis of Alcohol through Hydroboration/Oxidation of Alkenes**
**Objective:**
To draw the structural formula for the product formed upon hydroboration/oxidation of a given alkene.
**Chemical Structure Given:**
The initial alkene presented is a branched hydrocarbon:
- A double bond (C=C) is present between two carbon atoms.
- To the left of the double bond, a branched chain with:
- One methyl group (CH₃) attached to a central carbon (CH).
- Ethyl group (CH₃CH₂) extending from the central carbon atom.
- To the right of the double bond, a terminal hydrogen atom is bonded.
**Instructions:**
- Use wedge and hash bonds only for rings.
- Do not show stereochemistry in other cases.
- If the reaction produces a racemic mixture, just draw one stereoisomer.
**Hydroboration/Oxidation Process Overview:**
1. **Hydroboration:** Borane (BH₃) adds across the double bond in a syn-addition manner where boron attaches to the less substituted carbon.
2. **Oxidation:** The boron atom is replaced with a hydroxyl (-OH) group using hydrogen peroxide (H₂O₂) in an alkaline medium, forming an alcohol.
**Educational Note:**
The hydroboration/oxidation provides a regioselective method to convert alkenes into alcohols, avoiding carbocation rearrangement common in other hydration processes. This reaction gives anti-Markovnikov alcohols.
**Conclusion:**
Through this process, the structural representation of the alcohol product can be derived by carefully analyzing the original alkene structure and applying the mentioned reaction steps.
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