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Draw a structural formula for the major product of the reaction shown. Br2 CH2 H20

Draw a structural formula for the major product of the reaction shown. Br2 CH2 H20

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Reaction Problem:** **Question:** Draw a structural formula for the major product of the reaction shown. **Chemical Reaction Diagram Explanation:** The diagram shows a cyclopentene molecule reacting with bromine (Br₂) in the presence of water (H₂O). The chemical structure represents cyclopentene, which is a five-membered carbon ring with one double bond. The reaction conditions indicate a typical halohydrin formation process where the double bond will react with Br₂ in an aqueous environment, resulting in the formation of a bromohydrin. The major product will result from the anti-addition of bromine and a hydroxyl group across the double bond, following Markovnikov's rule. This means the bromine atom will attach to the less substituted carbon, and the hydroxyl group (from water) will attach to the more substituted carbon.
Transcribed Image Text:**Reaction Problem:** **Question:** Draw a structural formula for the major product of the reaction shown. **Chemical Reaction Diagram Explanation:** The diagram shows a cyclopentene molecule reacting with bromine (Br₂) in the presence of water (H₂O). The chemical structure represents cyclopentene, which is a five-membered carbon ring with one double bond. The reaction conditions indicate a typical halohydrin formation process where the double bond will react with Br₂ in an aqueous environment, resulting in the formation of a bromohydrin. The major product will result from the anti-addition of bromine and a hydroxyl group across the double bond, following Markovnikov's rule. This means the bromine atom will attach to the less substituted carbon, and the hydroxyl group (from water) will attach to the more substituted carbon.
**Instruction:** Draw a structural formula for the major product of the reaction shown. **Reaction:** - Reactant: - Structure: - Isopropene (also known as propene with two methyl groups attached to the central carbon) - Chemical formula: (CH₃)₂C=CH₂ - Reagents: - Bromine (Br₂) - Water (H₂O) **Explanation:** In this reaction, bromine (Br₂) and water (H₂O) are added across the double bond of the alkene. This typically leads to the formation of a halohydrin. The major product will have one bromine atom and one hydroxyl group (OH) added to the carbon atoms that were originally part of the double bond, following Markovnikov's rule, where the OH group attaches to the more substituted carbon atom.
Transcribed Image Text:**Instruction:** Draw a structural formula for the major product of the reaction shown. **Reaction:** - Reactant: - Structure: - Isopropene (also known as propene with two methyl groups attached to the central carbon) - Chemical formula: (CH₃)₂C=CH₂ - Reagents: - Bromine (Br₂) - Water (H₂O) **Explanation:** In this reaction, bromine (Br₂) and water (H₂O) are added across the double bond of the alkene. This typically leads to the formation of a halohydrin. The major product will have one bromine atom and one hydroxyl group (OH) added to the carbon atoms that were originally part of the double bond, following Markovnikov's rule, where the OH group attaches to the more substituted carbon atom.
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