Draw a straight line parallel to the base BC of the triangle ABC and meeting AB and AC (or produced) in D, E so that DE will be equal to (i) the sum of BD and CE; (ii) their difference. CONSTRUCTION: Bisect the /B to meet the bisectors of the C internally and externally in P and Q. Draw from P and Q the parallels D,PE, and QE,D2 to BC to meet AB and AC respectively in D1, D2 and E1, E2. Then E,D, and E,D2 are the two required lines '2• A Ez D2 B

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Q: Quesiton 24

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Q: 3) Consider the right triangle and find x: 6 X 5

A: Let,hypotenuse  : c = 6perpendicular  : a = 5base : b = x

Q: Use the following points: P(7,-5,5) Q(-5,10,10), R(-8,8,4), S(-20,23,1) A: Find the area of the…

A: Given points are: P(7,-5,5),Q(-5,10,10), R(-8,8,4), S(-20,23,1)

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A: Explanation and Solution is given below....