Draw a stepwise mechanism for the following reaction: Part 1 out of 4 H-Br finish structure ... OH HBr edit structure ... O HBr Br H₂O HO™ HOBr Br
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![### Educational Website Content
#### Reaction Mechanism for Alcohol and HBr
##### Objective:
Draw a stepwise mechanism for the reaction where an alcohol reacts with HBr to form an alkyl bromide.
**Reaction Equation:**
\[ \text{Alcohol} \, (\text{OH}) + \text{HBr} \rightarrow \text{Alkyl Bromide} \]
**Illustration:**
- **Reactants:** The starting compound is an alcohol with the -OH group attached to a carbon chain. It reacts with HBr.
- **Products:** The primary reaction product is an alkyl bromide where the bromine atom has replaced the hydroxyl group.
**Part 1 out of 4:**
- **Mechanistic Step:**
- The first part in the mechanism requires identifying the intermediate and the leaving group.
- The alcohol reacts with HBr, leading to the formation of a carbocation intermediate. The reaction is depicted with structural formulas.
- **Diagram Explanation:**
- **Left Structure:** Displays the starting compounds: an alcohol and HBr.
- **Middle Structure:** Shows the formation of a carbocation where the -OH group has left, indicating an incomplete structure needing further editing.
- **Right Section (Choices):** Options for the leaving group and other products are listed:
- \( \text{HBr} \)
- \( \text{Br}^- \) (Highlighted as correct)
- \( \text{H}_2\text{O} \)
- \( \text{HO}^- \)
- \( \text{HOB}_r \)
**Selection:**
The correct answer is marked, indicating the liberation of \( \text{Br}^- \) as the leaving group in this reaction step.
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This explanation demonstrates how the hydroxyl group in an alcohol is replaced by a bromine atom from HBr, resulting in alkyl bromide formation. Further steps will involve the completion of the mechanism, detailing carbocation stability and rearrangements if necessary.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb0d45dce-c646-4e67-b264-22576bb4d853%2F81fd4181-781d-4129-a514-4553d2ddc90a%2F7ntwgrk_processed.png&w=3840&q=75)
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