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Draw a sketch of f (x) = |-x² + 9 – 3 (you are welcome to use a graphing utility). Solve f (x) = 4. Your solutions need to be exact, not decimal approximations. As a reminder, if g (A) = |A], you can remove the absolute value by splitting into two different equations: g(A) = -A if A < 0 g(A) = A if A > 0

Draw a sketch of f (x) = |-x² + 9 – 3 (you are welcome to use a graphing utility). Solve f (x) = 4. Your solutions need to be exact, not decimal approximations. As a reminder, if g (A) = |A], you can remove the absolute value by splitting into two different equations: g(A) = -A if A < 0 g(A) = A if A > 0

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Draw a sketch of f (x) = |-x² +9 – 3 (you are welcome to use a graphing utility). Solve f (x) = 4. Your solutions need to be exact, not decimal approximations. As a reminder, if g (A) = |A|, you can remove the absolute value by splitting into two different equations: • g(A) = -A if A < 0 • g(A) = A if A >0
Transcribed Image Text:Draw a sketch of f (x) = |-x² +9 – 3 (you are welcome to use a graphing utility). Solve f (x) = 4. Your solutions need to be exact, not decimal approximations. As a reminder, if g (A) = |A|, you can remove the absolute value by splitting into two different equations: • g(A) = -A if A < 0 • g(A) = A if A >0
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