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(Drag and drop the missing words) In the integral dx Va? we may use x= and dx= substitutions to reduce the integral to do. This step requires that a>0 and |>0. Similarly, in the integral dx a? + x2 we may use x= Integrals like dx x2 – a? can also be evaluated by rather than trigonometric substitutions. However, the integral cannot. In this case, an appropriate substitution is x= and dx= partial fractions a sec e ratio test a cose de improper integral a sine cos e a tane law of cosines root test a sece tane de

(Drag and drop the missing words) In the integral dx Va? we may use x= and dx= substitutions to reduce the integral to do. This step requires that a>0 and |>0. Similarly, in the integral dx a? + x2 we may use x= Integrals like dx x2 – a? can also be evaluated by rather than trigonometric substitutions. However, the integral cannot. In this case, an appropriate substitution is x= and dx= partial fractions a sec e ratio test a cose de improper integral a sine cos e a tane law of cosines root test a sece tane de

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(Drag and drop the missing words) In the integral dx Va? – x2 we may use x= and dx= substitutions to reduce the integral to do. This step requires that a>0 and >0. Similarly, in the integral da a? + x2 we may use x= Integrals like dx x2 – a? can also be evaluated by rather than trigonometric substitutions. However, the integral cannot. In this case, an appropriate substitution is x3 and dx= partial fractions a sec e ratio test a cose de improper integral a sine cos e a tane law of cosines root test a sece tane de
Transcribed Image Text:(Drag and drop the missing words) In the integral dx Va? – x2 we may use x= and dx= substitutions to reduce the integral to do. This step requires that a>0 and >0. Similarly, in the integral da a? + x2 we may use x= Integrals like dx x2 – a? can also be evaluated by rather than trigonometric substitutions. However, the integral cannot. In this case, an appropriate substitution is x3 and dx= partial fractions a sec e ratio test a cose de improper integral a sine cos e a tane law of cosines root test a sece tane de
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