Dr. Suarez, a veterinarian, wants to estimate the average number of calories a Chihuahua normally eats in a day. He will take a sample of n Chihuahuas and create a 99% confidence interval, percent for caloric intake of no more than 10 calories. A pilot study suggests that Chihuahuas' daily has a standard deviation of 36 calories. Which of these is the smallest approximate sample size required to obtain the desired margin of error Select one: a.86 b.68 c.50 d.36 e.30

Q: Wheel thickness on a train is random because wear and tear causes the wheel to wear down. The…

A: We have given that,  Sample mean or average (x̄) = 8.29, standard deviation (σ) = 0.52 and sample…

Q: A study of a local high school tried to determine the mean number of text messages that each student…

A: In question, Given that A study of a local high school tried to determine the mean number of text…

Q: You measure 41 watermelons' weights, and find they have a mean weight of 47 ounces. Assume the…

A: Given that: n= 41.0 , x̄= 47.0 s= 2.5 At 90.0 % confidence level , z score= 1.645 So, 90.0 %…

Q: An Army official wants to estimate the mean weight of a particular type of weapon.  He takes a…

A: Given that, Mean = 48.1 Standard deviation = 0.12 Sample size = 100 98% confidence level

Q: A study of peach trees found that the average number of peaches per tree was 625.  The standard…

A:

Q: In a random sample of six people, the mean driving distance to work was 24.9 miles and the standard…

A: The sample size: n=6 Sample mean: x¯=24.9 miles Standard deviation: s=7.9 Confidence level: C=0.99…

Q: The heights of pine trees at a local tree farm are known to follow a normal distribution with a…

A: Given: Sample Sizen=99Sample MeanX=121Standard Deviationσ=7 The z value corresponding to the area…

Q: the standard deviation of the 16 observations was 0.95 inches (again, the sample mean was 17.2).…

A: Given :  Standard deviation of the 16 observations was 0.95 inches & the sample mean was 17.2.…

Q: A study of a local high school tried to determine the mean number of text messages that each student…

A:

Q: Sarah works for a coffee company. The farmers who supply the company spray Chemical X as a…

A: a) The statistical power of the current sampling scheme is calculated as follows, Thus, the…

Q: A local police department made an effort to determine the average speed of automobiles travelling…

A:

Q: he average weight of 20 randomly selected cars was 3500 pounds. The sample standard deviation was…

A: given data, n=20df=n-1=20-1=19x¯=3500 pounds s=315 pounds CI=0.90α=1-0.90=0.10

Q: You measure 43 randomly selected textbooks' weights, and find they have a mean weight of 33 ounces.…

A: We have to find 95% confidence interval for the true population mean textbook weight.

Q: A study was commissioned to find the mean weight of the residents in certain town. The study…

A: Given: n=58, x=174 and s=38. Now,Degrees of freedom=n-1=58-1=57 Then, at 95% confidence level, the…

Q: A large urgent care center with 4 doctors found that they can see an average of 28 patients per…

A: We have given that Sample size (n) = 41Sample mean (x̅) = 28Standard deviations (s) =…

Q: You measure 32 textbooks weight and find they have a mean weight of 67 ounces. Assume the standard…

A: Given: Sample size (n) = 32 Mean (x̄) = 67 ounces Population standard deviation (σ) = 8.302…

Q: Among those taking the Graduate Record Exam, 18 people are randomly selected. This group had a mean…

A:

Q: Find the 95% confidence interval (CI) and margin of error (ME) of the true mean weights of male…

A: As the population standard deviation is unknown, the t-test statistic to be used for estimating the…

Q: A runner wants to know her average mile running time. She records a sample of 25 running times. The…

A: Solution: Let X be the mile running time. From the given information, x-bar=6.5 minutes, s=0.7…

Q: You measure 29 backpacks' weights, and find they have a mean weight of 46 ounces. Assume the…

A:

Q: You measure 20 dogs' weights, and find they have a mean weight of 44 ounces. Assume the population…

A: Since we know population standard deviation, use z-distribution to find z-critical value. Find…

Q: You measure 41 watermelons' weights, and find they have a mean weight of 79 ounces. Assume the…

A: Mean = 79Standard deviation = 2.4Sample size = 41

Q: A popular weight loss program claims users will lose weight each month. Linda samples 25 dieters and…

A: We have given that,  Sample mean (x̄) = 10 pounds, standard deviation (s) = 2 pounds and sample size…

Q: You measure 24 turtles' weights, and find they have a mean weight of 34 ounces. Assume the…

A:

Q: A researcher has a sample of 49 arctic plants, and wants to describe the average plant height. The…

A: The distribution of sample average of these arctic plant heights is N(8.2, 1), which is obtained…

Q: Susan recently switched her primary doctor to one specializing in caring for elderly patients. On…

A:

Q: A random sample of 250 students at a university finds that these students take a mean of 15 credit…

A: Solution: From the given information, the 99% confidence interval for the mean credit hours is…

Q: A custodian wishes to compare two competing floor waxes to decide which one is best. He believes…

A: Let μ1 denotes the population mean of WaxWin, and μ2 denotes the population mean of WaxCo. The claim…

Q: You measure 34 turtles' weights, and find they have a mean weight of 65 ounces. Assume the…

A:

Q: Many cheeses are produced in the shape of a wheel. Because of the differences in consistency between…

A:

Q: he seasonal output of a new experimental strain of pepper plants was carefully weighed. The mean…

A: normal distribution ,μ=17σ=1.75n=200p(13<X<16)=?

Q: You measure 27dogs' weights, and find they have a mean weight of 63 ounces. Assume the population…

A:

Q: ou measure 25 randomly selected textbooks' weights, and find they have a mean weight of 73 ounces.…

A: Given : sample size = 25 Mean weight = 73 ounces Population standard deviation is 5.8 ounces…