ΔΡ. q = C,f (€) Quick-opening valve: 1 ( €) = Linear valve: f (e) = l Equal-percentage valve: 1 ( €) =R(-1 %3D
ΔΡ. q = C,f (€) Quick-opening valve: 1 ( €) = Linear valve: f (e) = l Equal-percentage valve: 1 ( €) =R(-1 %3D
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Book: Process Dynamics and Control, Third Edition or Fourth Edition, by D. E. Seborg, T. F. Edgar, D. A. Mellichamp, F. J. Doyle III, John Wiley & Sons, Inc, 2011
Transcribed Image Text:A circulating cooling water system is used to cool a hot oil stream in a shell and tube heat
exchanger. The cooling water is first pumped through a refrigerated cooler and then through the
heat exchanger. At the design flow rate of q = 500 gpm, the water pressure drop through the
refrigerated cooler is 15 psi, and the pressure drop through the heat exchanger is 25 psi. The
water pressure drops through the refrigerated cooler and heat exchanger are proportional to the
flow rate squared. The water supply pump produces a constant pressure head of 80 psig to
overcome pressure losses in the cooler, heat exchanger and control valve. At the end of the
circulating cooling water system, the pressure is at atmospheric pressure.
Assume an equal percentage control valve (R = 20) in which the stem position (I) = 0.50 at the
design flow rate. The specific gravity of the cooling water is 1.0
(a)
(b)
Determine the valve coefficient Cy.
Calculate the water flow rate in gpm through a wide-open control valve.
Information that may or may not be useful
'ΔΡ.
9 = C,f (€)
g.
Quick-opening valve: 1 ( € ) = vE
Linear valve: f ( l) = l
Equal-percentage valve: f ( €) = R-1
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