dout 2 *Property of STI Page 2 of 4 IT1903 Rounded - Since the problem states each Round – off Error = Actual Value – Rounded – off Numerical Value Round – off Error = 2.003458764 – 2.0035 Round – off Error = that number is represented by using 5 significant digits, thus the Rounded - off numerical value off Numerical Value Round – off Error = -0.000041236 0.666666666666 –

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Round-Off Error
1. Given:
2. Given:
3. Given:
Note that the e constant or
Actual Value =
Actual Value = :
0.666666666666 ...
Rounded –
Euler's
number
is
a
2.003458764
mathematical
constant.
Rounded –
The e constant is real and
off Numerical Value =
off Numerical Value =
irrational number that is
2.0035
0.66667
equal
to:
e =
2.718281828459...=
Solution:
Solution:
Round – off Error =
Actual Value –
Actual Value
*Property of STI
Page 2 of 4
03 Handout 2
STI
IT1903
Since the problem states
Rounded –
Round – off Error =
Actual Value –
off Numerical Value
Round – off Error =
2.003458764 – 2.0035
Round – off Error =
-0.000041236
that
each
number
is
Rounded –
represented by using 5
significant digits, thus the
Rounded
off Numerical Value
Round – off Error =
0.666666666666 –
- off numerical value
= e = 2.7183
0.66667
Round – off Error =
-0.000003333334
Solution:
Round – off Error =
Actual Value –
Rounded –
off Numerical Value
Round – off Error =
2.718281828459 –
2.7183
Round – off Error =
-0.000018171541
Transcribed Image Text:Round-Off Error 1. Given: 2. Given: 3. Given: Note that the e constant or Actual Value = Actual Value = : 0.666666666666 ... Rounded – Euler's number is a 2.003458764 mathematical constant. Rounded – The e constant is real and off Numerical Value = off Numerical Value = irrational number that is 2.0035 0.66667 equal to: e = 2.718281828459...= Solution: Solution: Round – off Error = Actual Value – Actual Value *Property of STI Page 2 of 4 03 Handout 2 STI IT1903 Since the problem states Rounded – Round – off Error = Actual Value – off Numerical Value Round – off Error = 2.003458764 – 2.0035 Round – off Error = -0.000041236 that each number is Rounded – represented by using 5 significant digits, thus the Rounded off Numerical Value Round – off Error = 0.666666666666 – - off numerical value = e = 2.7183 0.66667 Round – off Error = -0.000003333334 Solution: Round – off Error = Actual Value – Rounded – off Numerical Value Round – off Error = 2.718281828459 – 2.7183 Round – off Error = -0.000018171541
Find the round-off error of
the following using 5
significant digits:
1. 1
3
2. tan 150
3. 1 — п
4. V115
5. In 12
Transcribed Image Text:Find the round-off error of the following using 5 significant digits: 1. 1 3 2. tan 150 3. 1 — п 4. V115 5. In 12
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