In (Figure 1), the man has a mass of 75 kg and the crate has a mass of 130 kg. The coefficient of static friction between his shoes and the ground is μs = 0.4 and between the crate and the ground is μc = 0.3. Determine if the man is able to move the crate using the rope-and-pulley system shown.In (Figure 1), the man has a mass of 75 kg and the cratehas a mass of 130 kg. The coefficient of static frictionbetween his shoes and the ground is ug = 0.4 andbetween the crate and the ground is µc = 0.3.The man can move the crateThe man cannot move the crate.SubmitRequest AnswerPart BFigure1 of 1Prove your answer to part A by calculating the static frictional force F between the man's shoes and the ground required to movethe crate and the maximum static frictional force Fmax which can be developed.Express your answers in newtons to three significant figures separated by a com_ma.vecF, Fmax =N45°30SubmitRequest AnswerProvide FeedbackNext >P Pearson

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Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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In (Figure 1), the man has a mass of 75 kg and the crate has a mass of 130 kg. The coefficient of static friction between his shoes and the ground is μs = 0.4 and between the crate and the ground is μc = 0.3.

Determine if the man is able to move the crate using the rope-and-pulley system shown.
In (Figure 1), the man has a mass of 75 kg and the crate
has a mass of 130 kg. The coefficient of static friction
between his shoes and the ground is ug = 0.4 and
between the crate and the ground is µc = 0.3.
The man can move the crate
The man cannot move the crate.
Submit
Request Answer
Part B
Figure
1 of 1
Prove your answer to part A by calculating the static frictional force F between the man's shoes and the ground required to move
the crate and the maximum static frictional force Fmax which can be developed.
Express your answers in newtons to three significant figures separated by a com_ma.
vec
F, Fmax =
N
45°
30
Submit
Request Answer
Provide Feedback
Next >
P Pearson

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