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= $2000e0.06x35 35 [ e-0.06t 35 = $2000e2.1 161105 = −$33,333.33e².¹ (e−0.06×35 — e−0.06x0) ,-0.06t dt -0.06 Simplified further as, FV = −$33,333.33e².1 (e-².1 — eº) = −$33333.33 + $33333.33e².1 ≈$238,872

= $2000e0.06x35 35 [ e-0.06t 35 = $2000e2.1 161105 = −$33,333.33e².¹ (e−0.06×35 — e−0.06x0) ,-0.06t dt -0.06 Simplified further as, FV = −$33,333.33e².1 (e-².1 — eº) = −$33333.33 + $33333.33e².1 ≈$238,872

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How do you get -33,333 in this problem

= $2000e0.06x35 0 = 35 -0.06t dt 35 601105 $2000e².1 ,-0.06t -0.06 = −$33,333.33e².¹ (e- -0.06x35 -0.06x0 (e-0.0 e Simplified further as, FV = -$33,333.33e².1 (e-2.1-e0) = −$33333.33 + $33333.33e².1 ~$238,872
Transcribed Image Text:= $2000e0.06x35 0 = 35 -0.06t dt 35 601105 $2000e².1 ,-0.06t -0.06 = −$33,333.33e².¹ (e- -0.06x35 -0.06x0 (e-0.0 e Simplified further as, FV = -$33,333.33e².1 (e-2.1-e0) = −$33333.33 + $33333.33e².1 ~$238,872
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