$15. Construct a confidence interval at a 99% confidence level.
Q: Suppose that 18% of a random sample of 2307 Miami residents said that they will donate blood in…
A: we have given that sample size =n=2307 ,sample proportion =p^=18%=0.18
Q: You're considering going to graduate school, and you would like to know how many people would…
A:
Q: If n-25, -46, and s-5, construct a confidence interval at a 95% confidence level. Assume the data…
A: Givenn=25x=46s=5confidence level = 95%
Q: Eric is studying people's typing habits. He surveyed 525 people and asked whether they leave one…
A:
Q: A survey asked, "How many tattoos do you currently have on your body?" Of the 1209 males surveyed,…
A:
Q: a) Create a 90% confidence interval for the level of cheating among high school students. Don't…
A: It is given that Sample size n = 4500 Sample proportion = 0.74 Level of confidence = 90% Note :…
Q: A health researcher computed 90%, 95%, 98%, and 99% confidence intervals for the proportion of…
A: Given that a health researcher computed 90%, 95%, 98%, and 99% confidence intervals for the…
Q: 132,000 189,000 270,000 324,800 269,000 340,000 222,000 135,000 169,900 310,000 142,900 86,000…
A: Given information: x 132000 324800 222000 310000 285000 189000 269000 135000…
Q: Express the confidence interval (78.7 % , 96.3 % ) in the form of p+ ME. %士 Question Help: Video…
A: Given,confidence interval(CI)=(78.7% , 96.3%)
Q: A poll reported that only 502 out of a total of 1685 adults in a particular region said they had a…
A: Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…
Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…
A: Let x be the number of people who are willing to take a second or part-time job. It is given that…
Q: Determine the sample size for a on-line survey with a variability of 30% and a 95% confidence…
A: Sample size n=z2(p*q)/e2
Q: 318 who said yes. What proportion of the students does not read story books? Use 95% confidence…
A: We have given that Sample size n = 1000 Favorable cases x = 318 Sample proportion p^=x/n =318/1000…
Q: Interpret the confidence interval. O If Pew Research Center took many samples, 98% of them would…
A: Confidence interval gives the range of values between which the parameter falls with some…
Q: If n=32, ¯xx¯(x-bar)=36, and s=10, construct a confidence interval at a 99% confidence level. Assume…
A:
Q: one city, 79.6% of the 8500 students surveyed said they eat at the school cafeteria. Find the 95%…
A: Given n=8500
Q: A research group asked 4488 Americans how they fall asleep, and 536 of them fall asleep on their…
A:
Q: Find ??/2 for the 93% confidence interval. Select one: A. 1.83 B. 1.81 C. 1.80 D. 1.82
A: Solution: Given information: Confidence level = 93% = 0.93 α=1-confidence level α=1-0.93= 0.07…
Q: Construct the confidence interval for the population mean . C=0.98, x=15.3, = 10.0, and n=75
A: The Confidence Interval formula is X ± Z s √(n) Where: X is the mean Z is the Z-value…
Q: If n=30, 7(x-bar)=49, and s=14, construct a confidence interval at a 99% confidence level. Assume…
A:
Q: Use the confidence interval to find the margin of error and the sample mean. (0.072,0.210) The…
A: Given Confidence of interval (0.072,0.210)
Q: Presidential Travel In a survey of 1004 individuals, 442 felt that President George W. Bush spent…
A:
Q: e a sample of 306 suspected crimina 85% confidence interval for the pop O Most Wanted list. Round…
A: We need to construct the 85% confidence interval for the population proportion. A confidence…
Q: Find z for a 90% confidence level. Round your answer to two decimal places.
A: Given confidence level is 90% Significance level is 10%
Q: Which of the following would result in the narrowest confidence interval? A sample size of 30 with…
A: Here we will use the concept of confidence interval and using the formula of confidence interval we…
Q: Education Television In a random sample of 200 people, 154 said that they watched educational…
A: Given that, X = 154 N = 200 90% confidence level
Q: A survey of 127 patients in a particular hospital determined that 54% of them felt that they were…
A: The sample proportion of patients felt they were receiving excellent care (p-cap) is 0.54. The…
Q: About 74% of MCC students believe they can achieve the American dream and about 65% of Ferris State…
A: The provided data is,
Q: State the equation for the 95% confidence interval?
A: The equation for confidence interval can be stated as: Here x̅ is the sample mean, Zα/2 is the…
Q: Which of the common confidence levels (90%, 95%, or 99%) would you prefer to use if you wanted to…
A: Introduction: The “smallest” confidence interval implies the confidence interval with the shortest…
Q: Determine whether the statement below makes sense or does not make sense. Explain clearly.
A: Here given , Based on our sample, the 95% confidence interval for the mean amount of television…
Q: Construct the 99% confidence interval for the difference when 3-47688, -318.32, -42.11, -2680, -19,…
A: Test hypothesisNull Hypothesis H0: μ1=μ2Alternative Hypothesis Ha: μ1≠μ2For group 1 Sample size…
Q: Construct and interpret a confidence interval to estimate the mean height of the population. You…
A:
Q: Describe when you would use a t-score instead of a z-score when finding a confidence interval.
A: Describe in what conditions t-score would be used instead of a z-score when finding a confidence…
Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a…
A:
Q: If n=550 and X = 440, construct a 90% confidence interval. Give your answers to three decimals <p<
A:
Q: Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of…
A: Solution
Q: At one large college, 1867 out of the 2500 students surveyed said they plan to take another science…
A: The known values are, p^=1,867/2,500=0.7468, n=2,500. Using standard normal table, the critical…
Q: Translate the statement into a confidence interval. Approximate the level of confidence. In a survey…
A: as per our company guidelines we are supposed to answer only first question. Kindly repost other…
Q: You observe 40 customers at a coffee shop, and 77% of them tip. What is the 95% confidence interval…
A: p=0.77 n=400
Q: In a survey, 1000 Grade 7 students were asked if they read storybooks. There were 318 who said Yes.…
A: Givenn=1000x=318p^=3181000=0.318Confidence interval = 95%
Q: Use the data in the table to the right to answer the following questions. Find the sample proportion…
A: From the provided information, Total candy (n) = 41 Total red candy (x) = 7 The required proportion…
Q: find tc for a 95% confidence level when the sample size is 6.
A: level of significance, alpha = 0.05from standard normal table, two tailed t alpha/2 with n-1 = 6 d.f…
Given that
Sample size n = 24
Sample mean = 33
Sample SD = 15
The critical value of t at (n - 1) = 23 df and at 99% confidence level is 2.807
Step by step
Solved in 2 steps with 1 images
- Find the confidence level and α for an 80% confidence interval.Determine whether the statement below makes sense or does not make sense. Explain clearly. Based on our sample, the 95% confidence interval for the mean amount of television watched by adults in a nation is 3.5 to 4.1 hours per day. Therefore, there is 95% chance that the mean for all adults in the nation will fall somewhere in this range and a 5% chance that it will not. Choose the correct answer below. O A. The statement makes sense. There is 95% probability that the confidence interval limits actually contain the true value of the population mean, so the probability it does not fall in this range is 100% - 95% = 5%. O B. The statement does not make sense. The probability the population mean is greater than the upper limit is 5% and the probability it is less than the lower limit is 5%, so the probability it does not is 5% + 5% = 10%. O C. The statement makes sense. There is 5% probability that the confidence interval limits do not contain the true value of the sample mean, so the…A random sample of 40 12th-grade students was asked how long it took to get to school. The sample mean was 15.5 minutes and the sample standard deviation was 12.7 minutes. a. Find a 95% confidence interval for the population mean time it takes 12th-grade students to get to school. b. Would a 90% confidence interval based on this sample data be wider or narrower than the 95% confidence interval? Explain. Check your answer by constructing a 90% confidence interval and comparing the width of the interval with the width of the 95% confidence interval you found in part (a). a. The 95% confidence interval is from minutes to minutes. (Round to two decimal places as needed. Use ascending order.) b. Would a 90% confidence interval based on this sample be wider or narrower than the 95% confidence interval? O A. The 90% interval is wider because it has a lower confidence level, and therefore uses a smaller critical value, which creates a wider interval. O B. The 90% interval is wider because it…
- At one large college, 660 out of the 1500 students surveyed said they plan to take another science class.Find the 95% confidence interval for the proportion of students that said they plan to take another science class.Drug Tests There is a 3.9% rate of positive drug test results among workers in the United States (based on data from Quest Diagnostics). Assuming that this statistic is based on a sample of size 2000, construct a 95% confidence interval estimate of the percentage of positive drug test results. Write a brief statement that interprets the confidence interval.Find the confidence level and α for an 86% confidence interval. What is the confidence level? Determine the value of α.
- Tonya wants to estimate what proportion of her school's seniors plan to attend the prom. She interviews an SRS of 50 of the 750 seniors in her school and finds that 36 plan to go to the prom. Tonya then calculates a 90% confidence interval of (0.616, 0.824). Interpret Tonya's interval in context. 90% of the seniors at Tonya's high school are between 61.6% and 82.4% likely to attend prom. We can be 90% confident that the sample proportion is captured by the confidence interval. We are 90% confident that the interval from 0.616 to 0.824 captures the true proportion of all seniors at Tonya's high school who plan to attend the prom. O If Tonya took many samples, 90% of them would find that 72.4% of the seniors in the sample plan on attending prom. The percent of seniors at Tonya's high school who plan to attend the prom is certain to be between 61.6% and 82.4%. terms of use contact us help careers privacy policy about usName: Statistics 1. An investigative reporter contacts a random sample of hotels, and finds a 95% confidence interval for the proportion of hotels in the United States that have reported having bedbugs is (0.04, 0.11). a. Interpret this confidence interval in context. F3 80 b. A national hospitality organization had reported that only 5% of hotels have experienced problems with bedbugs. Does this reporter have compelling evidence that the true proportion is really higher? Explain. c. How could the reporter estimate this proportion with a smaller margin of error? a. Identify the parameter, p, 2. To estimate how often someone runs a red light in Cyber City, a student watched traffic for a while at several randomly selected intersections. Drivers ran the red light during 43 of 240 light changes she observed. Q O Period: Quiz (ch 16+17) F4 9 F5 Page 1 / 2 c F6 8 + F7 Date: : DII F8 DD F9Which of the following would result in the widest confidence interval? A sample size of 30 with 95% confidence. A sample size of 100 with 95% confidence A sample size of 100 with 99% confidence. A sample size of 30 with 99% confidence.