Does the series ) converge absolutely, converge conditionally or diverge? VKA + 8 k=1 converges absolutely converges conditionally diverges 1)* converge absolutely, converge conditionally or diverge? Does the series k=1 Vk4 + 8 converges absolutely converges conditionally diverges

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Question
## Series Convergence Questions

### Question 1:
Does the series \(\sum_{k=1}^{\infty} \frac{1}{\sqrt[3]{k^4 + 8}}\) converge absolutely, converge conditionally, or diverge?

- ○ converges absolutely
- ○ converges conditionally
- ○ diverges

### Question 2:
Does the series \(\sum_{k=1}^{\infty} \frac{(-1)^k}{\sqrt[3]{k^4 + 8}}\) converge absolutely, converge conditionally, or diverge?

- ○ converges absolutely
- ○ converges conditionally
- ○ diverges

Each question requires determining the type of convergence or divergence for the provided series. Analyze the series by applying relevant convergence tests, such as the comparison test, ratio test, or alternating series test, to determine the correct choice.
Transcribed Image Text:## Series Convergence Questions ### Question 1: Does the series \(\sum_{k=1}^{\infty} \frac{1}{\sqrt[3]{k^4 + 8}}\) converge absolutely, converge conditionally, or diverge? - ○ converges absolutely - ○ converges conditionally - ○ diverges ### Question 2: Does the series \(\sum_{k=1}^{\infty} \frac{(-1)^k}{\sqrt[3]{k^4 + 8}}\) converge absolutely, converge conditionally, or diverge? - ○ converges absolutely - ○ converges conditionally - ○ diverges Each question requires determining the type of convergence or divergence for the provided series. Analyze the series by applying relevant convergence tests, such as the comparison test, ratio test, or alternating series test, to determine the correct choice.
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