A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 20 subjects had a mean wake time of 95.3 min and a standard deviation of 40.9 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 98% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Question content area bottom Part 1 Find the confidence interval estimate. enter your response here min<σ
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A: Given That The sample size is n=16 The sample mean is X=91.6 The sample standard deviation is s=40.1…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Obtain the 98% confidence interval estimate of the standard deviation of the mean wake times for a…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Obtain the 90% confidence interval estimate of the mean wake time for a population with the…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
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Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: The degrees of freedom is, df=n-1=23-1=22 The degrees of freedom is 22. Critical value for χU2 : The…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with…
A:
Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
A:
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: We have to find ci.
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: The sample size is 16, the sample mean is 97.8 and the sample standard deviation is 22.6.
Q: and after the treatment. The changes (before-after) in their levels of LDL cholesterol (in mg/dL)…
A: Given n=sample size=49, Sd=17.1, mean difference x̄d=2.8 Level of significance ɑ=0.05
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: Given Information: Sample size n=43 Sample mean x¯d=3.2 Sample standard deviation sd=17.9 Confidence…
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Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
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Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Assume that µ is the true mean wake time for a population with the drug treatment.
Q: drug for treating insomnia in older subjects. Before treatment, 13 subjects had a mean wake time of…
A: Given Xbar=95.3 Standard deviation=23.2
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
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Q: In a test of the effectiveness of garlic for lowering cholesterol, 43 subjects were treated with…
A: Sample mean = x̅ = 4.5 Sample size = n = 43 Sample S.D = s = 16.8 Standard Error = s/√n =…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
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Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Given data,n=15x=91.8s=42.7α=0.10t-critical value at α=0.10 and df=14 is tc=1.761
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Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
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Q: Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the…
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Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Sample size, n=20 Sample standard deviation, s = 43.9
Q: clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older…
A: Given n=26, x̄=95.2, s=40.7 ɑ=0.02
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A: sample size(n)=49Mean()=3.6standard deviation(s)=17.7confidence level=90%
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
A: Obtain the 90% confidence interval estimate of the standard deviation of the wake times for a…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Let μa denotes the true population mean for after treatment. Let xb¯ and xa¯ denote the sample mean…
Q: In a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with…
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Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Given Mean=97.1 Standard deviations=21.3 Sample size=14
Q: A clinic trial was conducted to test the effectiveness of drug for treating insomnia in older…
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A: Given that Sample size n = 21 Sample SD s = 43.5 We have to find the 90% confidence interval for…
Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
A: Since population standard deviation is unknown, Use t-distribution to find t-critical value. Find…
Q: A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in…
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Q: A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older…
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by Bartleby Expert- In a test of the effectiveness of garlic for lowering cholesterol, 48 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before - after) in their levels of LDL cholesterol (in mg/dL) have a mean of 5.5 and a standard deviation of 19.8. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view at distribution table. Click here to view page 1 of the standard normal distribution table, Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? O mg/dL < µA clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 26 subjects had a mean wake time of 97.5 min and a standard deviation of 43.3 min. Assume that the 26 sample values appear to be from a normally distributed population and construct a 98% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective?A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 24 subjects had a mean wake time of 90.7 min and a standard deviation of 41.3 min. Assume that the 24 sample values appear to be from a normally distributed population and construct a 95% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. ___min <σ<___ minA clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 20 subjects had a mean wake time of 105.0 min. After treatment, the 20 subjects had a mean wake time of 82.5 min and a standard deviation of 22.5 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 105.0 min before the treatment? Does the drug appear to be effective? Construct the 90% confidence interval estimate of the mean wake time for a population with the treatment. ???? min<μ<???? minA clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 23 subjects had a mean wake time of 93.6 min and a standard deviation of 43.8 min. Assume that the 23 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. minA clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 17 subjects had a mean wake time of 103.0 min. After treatment, the 17 subjects had a mean wake time of 96.4 min and a standard deviation of 23.7 min. Assume that the 17 sample values appear to be from a normally distributed population and construct a 95% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 103.0 min before the treatment? Does the drug appear to be effective? Construct the 95% confidence interval estimate of the mean wake time for a population with the treatment. min<μ< min (Round to one decimal place as needed.)A clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 16 subjects had a mean wake time of 104.0 min. After treatment, the 16 subjects had a mean wake time of 78.7 min and a standard deviation of 21.2 min. Assume that the 16 sample values appear to be from a normally distributed population and construct a 99% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 104.0 min before the treatment? Does the drug appear to be effective? Construct the 99% confidence interval estimate of the mean wake time for a population with the treatment. nothing min<μ<nothing min (Round to one decimal place as needed.) What does the result suggest about the mean wake time of 104.0 min before the treatment? Does the drug appear to be effective? The confidence interval ▼ does not include includes the mean wake…A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 20 subjects had a mean wake time of 92.5 min and a standard deviation of 43.9 min. Assume that the 20 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. minA clinical trial was conducted to test the effectiveness of a drug for treating insomnia in older subjects. Before treatment, 16 subjects had a mean wake time of 105.0 min. After treatment, the 16 subjects had a mean wake time of 95.3 min and a standard deviation of 23.5 min. Assume that the 16 sample values appear to be from a normally distributed population and construct a 99% confidence interval estimate of the mean wake time for a population with drug treatments. What does the result suggest about the mean wake time of 105.0 min before the treatment? Does the drug appear to be effective?A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 26 subjects had a mean wake time of 91.3 min and a standard deviation of 43.4 min. Assume that the 26 sample values appear to be from a normally distributed population and construct a 98% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Question content area bottom Part 1 Find the confidence interval estimate.A clinical trial was conducted to test the effectiveness of a drug used for treating insomnia in older subjects. After treatment with the drug, 11 subjects had a mean wake time of 97.2 min and a standard deviation of 43.4 min. Assume that the 11 sample values appear to be from a normally distributed population and construct a 90% confidence interval estimate of the standard deviation of the wake times for a population with the drug treatments. Does the result indicate whether the treatment is effective? Find the confidence interval estimate. (answer) min less then σ less than (answer) minIn a test of the effectiveness of garlic for lowering cholesterol, 49 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before- after) in their levels of LDL cholesterol (in mg/dL) have a mean of 3.1 and a standard deviation of 15.8. Construct a 95% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean µ? mg/dL mg/dL<µ< (Round to two decimal places as needed.) What does the confidence interval suggest about the effectiveness of the treatment? O A. The confidence interval limits contain 0, suggesting that the…SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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