Does anyone have any idea what rem and temp stands for in the code? JAVA
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Does anyone have any idea what rem and temp stands for in the code? JAVA
![public class CubesDigit {
public static void main(String[] args) {
int sum, rem, temp, a, b, c;// Declared variables
// for loop
for (int i = 100; i <= 999; i++) {
// body inside for loop
sum = 0;// initialization sum
int n = i;//Assign i variable into n variable
temp = n;//Assign n variable into temp variable
while (n > 0) {//test expression
rem = n % 10;//Mod by 10
n = n / 10;//divide by 10
sum = sum + (rem * rem * rem);
if (temp == sum) {
a = temp % 10;//Mod by 10
temp = temp / 10;//divide by 10
b = temp % 10;//Mod by 10
temp = temp / 10;//divide by 10
C = temp;//Assign temp value into c
System.out.println(sum +
+ c + "^3+" + b + "^3+" + a + "^3");//display output](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd94649eb-e984-4c5e-b96d-b802bfcef406%2Fb26ef69e-2754-416d-84b0-4cf642b80ccc%2Fg25wklr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:public class CubesDigit {
public static void main(String[] args) {
int sum, rem, temp, a, b, c;// Declared variables
// for loop
for (int i = 100; i <= 999; i++) {
// body inside for loop
sum = 0;// initialization sum
int n = i;//Assign i variable into n variable
temp = n;//Assign n variable into temp variable
while (n > 0) {//test expression
rem = n % 10;//Mod by 10
n = n / 10;//divide by 10
sum = sum + (rem * rem * rem);
if (temp == sum) {
a = temp % 10;//Mod by 10
temp = temp / 10;//divide by 10
b = temp % 10;//Mod by 10
temp = temp / 10;//divide by 10
C = temp;//Assign temp value into c
System.out.println(sum +
+ c + "^3+" + b + "^3+" + a + "^3");//display output

Transcribed Image Text:Find all numbers between 100 and 999 that are equal to the sum of the cubes
of their digits. Print out all of your answers in this format:
153 = 1^3 + 5^3 + 3^3
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