Need B, C and D please Do the needs of patients in the emergency room differ for those who come by car vs. those by ambulance? Of the randomly selected emergency room patients who came by car, 54 had an injury, 53 were sick, 37 had heart problems, and 67 had other needs. Of the randomly selected emergency room patients who came by ambulance, 45 had an injury, 22 were sick, 43 had heart problems, and 30 had other needs. Conduct the appropriate hypothesis test using an α = 0.01 level of significance.a. What is the correct statistical test to use?- Homogeneity- Goodness-of-Fit- Independence- Paired t-testb. What are the null and alternative hypotheses?H₀:- O Means of transportation to the emergency room and emergency room needs are independent.- O The distribution of emergency room needs for patients who come by car is the same as it is for patients who come by ambulance.- O The distribution of emergency room needs for patients who come by car is not the same as it is for patients who come by ambulance.- O Means of transportation to the emergency room and emergency room needs are dependent. **Educational Website Text: Hypothesis Testing and Analysis****Hypothesis (H₁):**- The distribution of emergency room needs for patients who come by car is the same as it is for patients who come by ambulance.- Means of transportation to the emergency room and emergency room needs are independent.- Means of transportation to the emergency room and emergency room needs are dependent.- The distribution of emergency room needs for patients who come by car is not the same as it is for patients who come by ambulance.**c. Test-statistic for this data:** - Enter your calculated value here. (Please show your answer to three decimal places).**d. P-value for this sample:** - Enter your calculated value here. (Please show your answer to four decimal places).**e. The p-value is:** - Select whether the p-value is less than, greater than, or equal to the significance level (α).**f. Based on this, we should:**- Accept the null hypothesis.- Reject the null hypothesis.- Fail to reject the null hypothesis.**g. Thus, the final conclusion is:**- There is sufficient evidence to conclude that the distribution of emergency room needs for patients who come by car is the same as it is for patients who come by ambulance.- There is insufficient evidence to conclude that the distribution of emergency room needs for patients who come by car is not the same as it is for patients who come by ambulance.- There is insufficient evidence to conclude that the means of transportation to the emergency room and emergency room needs are dependent.- There is sufficient evidence to conclude that the means of transportation to the emergency room and emergency room needs are dependent.- There is sufficient evidence to conclude that the distribution of emergency room needs for patients who come by car is not the same as it is for patients who come by ambulance.**Discussion:**This section guides students through the hypothesis testing process in a research context involving emergency room needs and transportation modes. It encourages analytical thinking by requiring the calculation and interpretation of statistical data such as the test-statistic and p-value, leading to conclusions about the hypothesis's validity.

CarAmbulanceTotalInjury544599Sick532275Heart problem374380Other needs673097Total211140351a) (A) The correct statistical test to be used for the given scenario is Chi square test for homogeneity.b) (B) Null hypothesis: H0: The distribution of emergency room needs for patients who come by car is the same as it is for patients who come by ambulance.(D) Alternate hypothesis: HA: The distribution of emergency room needs for patients who come by car is not the same as it is for patients who come by ambulance.For this analysis, the significance level is 0.01. Using the sample data, we will conduct a chi-square test for Homogeneity.c)Use the given data to form a table consisting of observed frequency, expected probability, expected frequency and chi square statistics. Formula for the expected frequency is: CarExpectedAmbulanceExpectedTotalInjury54600.51066645390.7696599Sick53451.38935622302.0939675Heart problem37482.55793343323.8855280Other needs67581.29490630391.9516197Total2112115.7528611401408.70074351Use the table to determine the chi-square statistic, degree of freedom and P-value. d)Use the excel formula, "=CHISQ.DIST.RT(14.454,3)" for determining the P-value from the chi-square statistic having degrees of freedom 3. e) Since the P-value (0.0023) is less than the significance level (0.01), we have to reject the null hypothesis.f) Reject the null hypothesis.g) E) There is sufficient evidence to conclude that the distribution of emergency room needs for patients who come by car is not the same as it is for patients who come by ambulance.a) (A) The correct statistical test to be used for the given scenario is Chi square test for homogeneity.b) (B) Null hypothesis: H0: The distribution of emergency room needs for patients who come by car is the same as it is for patients who come by ambulance.(D) Alternate hypothesis: HA: The distribution of emergency room needs for patients who come by car is not the same as it is for patients who come by ambulance.For this analysis, the significance level is 0.05. Using the sample data, we will conduct a chi-square test for Homogeneity.c) d) P-value = 0.0023e) Since the P-value (0.0023) is less than the significance level (0.01), we have to reject the null hypothesis.f) Reject the null hypothesis.g) E) There is sufficient evidence to conclude that the distribution of emergency room needs for patients who come by car is not the same as it is for patients who come by ambulance.