solve, show all steps and fbd. do not provide copied answer or I will report Do problem 12 -22 using double integration. Also find how much additional deflection is added (to the max) if we account for the beam self-weight. Find this additional deflection using the table in appendix C. mechanics of materials chapter 12 (integration of moment)= theta, and integration of theta = v 13.5814VυvVL201APPENDIXCVV01Simply Supported Beam Slopes and DeflectionsBeamSlope-0₁L--0₁aL2교WOmaxL-L-max max02LL2PVmax+-bL20₂02Wo10₂ MoXWX-XXXX0₁02020₁0₂0₁ =Omax0 max=02==0₁====SLOPES AND=DEFLECTIONS OFBEAMS=-Pab(L + b)6EIL=Pab(L + a)6EIL-PL²16EI-MOL6EIMOL3EI-wL24EI-3wL³128EI7wL³384EI-7woĽ³360EIWOL³45EIV01.-01x=a=DeflectionUmaxVUmax- Pba6EIL=-Mo L²9√/3 EIat x = 0.5774L=Vmax|x=L/2²([² - 6² - a²)=-PL³48EI-5wL4384EI=-5wL4768EISSVmax = -0.006563at x = 0.4598LVmax = -0.00652-at x = 0.5193LWL4EIWOL4EIV =- Px48EI0 ≤ x ≤ L/2V =V==0≤x≤ aV =Elastic CurveV=-Pbx6EILV =V==(31²-WX384EI-Mox6EIL-WX24EI(L² − b² − x²)0≤x≤L/2-wL384EI-4x²)(x³ - 2Lx² + L²³)L/2 ≤ x foream'srcularsdiameter ofe seyA6 kN•mA-Xgrad avand ordeniominellet bus 900is1.5 mX8 kNCProb. 12-2112-22. Determine the elastic curve for the cantileveredW14 x 30 beam using the x coordinate. Specify the maximumslope and maximum deflection. E = 29(10³) ksi.9 ft1.5 mProb. 12-22B6 kN•mHT3 kip/ftBA12-2loadvertmax

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Answered: Do problem 12 -22 using double…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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solve, show all steps and fbd. do not provide copied answer or I will report

Do problem 12 -22 using double integration. Also find how much additional deflection is added (to the max) if we account for the beam self-weight. Find this additional deflection using the table in appendix C.

mechanics of materials chapter 12 (integration of moment)= theta, and integration of theta = v

13.5
814
V
υ
v
V
L
2
01
APPENDIX
C
V
V
01
Simply Supported Beam Slopes and Deflections
Beam
Slope
-0₁
L-
-0₁
a
L
2
교
W
Omax
L
-L-
max max
02
L
L
2
P
Vmax
+-b
L
2
0₂
02
Wo
1
0₂ Mo
X
W
X
-X
X
X
X
0₁
02
02
0₁
0₂
0₁ =
Omax
0 max
=
02
=
=
0₁
=
=
=
=
SLOPES AND
=
DEFLECTIONS OF
BEAMS
=
-Pab(L + b)
6EIL
=
Pab(L + a)
6EIL
-PL²
16EI
-MOL
6EI
MOL
3EI
-wL
24EI
-3wL³
128EI
7wL³
384EI
-7woĽ³
360EI
WOL³
45EI
V
01.-0
1x=a
=
Deflection
Umax
V
Umax
- Pba
6EIL
=
-Mo L²
9√/3 EI
at x = 0.5774L
=
Vmax
|x=L/2
²([² - 6² - a²)
=
-PL³
48EI
-5wL4
384EI
=
-5wL4
768EI
SS
Vmax = -0.006563
at x = 0.4598L
Vmax = -0.00652-
at x = 0.5193L
WL4
EI
WOL4
EI
V =
- Px
48EI
0 ≤ x ≤ L/2
V =
V=
=
0≤x≤ a
V =
Elastic Curve
V=
-Pbx
6EIL
V =
V=
=
(31²
-WX
384EI
-Mox
6EIL
-WX
24EI
(L² − b² − x²)
0≤x≤L/2
-wL
384EI
-
4x²)
(x³ - 2Lx² + L²³)
L/2 ≤ x <L
(16x³ - 24Lx² +9L³)
(Ľ² - x²)
-wox
360EIL
(8x³ - 24Lx²
+17L²x-L
(3x4 - 10L²x² +

for
eam's
rculars
diameter of
e sey
A
6 kN•m
A
-X
grad avand ordenio
minellet bus 900is
1.5 m
X
8 kN
C
Prob. 12-21
12-22. Determine the elastic curve for the cantilevered
W14 x 30 beam using the x coordinate. Specify the maximum
slope and maximum deflection. E = 29(10³) ksi.
9 ft
1.5 m
Prob. 12-22
B
6 kN•m
HT
3 kip/ft
B
A
12-2
load
vert
max

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