Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![### Dividing Rational Expressions Involving Multivariate Quadratics
#### Problem Statement
**Divide:**
\[
\frac{x^2 - 12xy + 20y^2}{x^2 - 4y^2} \div \frac{3x - 6y}{x + 2y}
\]
**Simplify** your answer as much as possible.
#### Explanation
To divide these rational expressions, follow these steps:
1. **Rewrite the division as a multiplication by the reciprocal:**
\[
\frac{x^2 - 12xy + 20y^2}{x^2 - 4y^2} \times \frac{x + 2y}{3x - 6y}
\]
2. **Factor all polynomials:**
- The numerator \(x^2 - 12xy + 20y^2\) can be factored as \((x - 2y)(x - 10y)\).
- The denominator \(x^2 - 4y^2\) is a difference of squares, which factors as \((x - 2y)(x + 2y)\).
- The numerator \(3x - 6y\) can be factored as \(3(x - 2y)\).
Therefore, we have:
\[
\frac{(x - 2y)(x - 10y)}{(x - 2y)(x + 2y)} \times \frac{x + 2y}{3(x - 2y)}
\]
3. **Cancel out common factors:**
- Cancel \( (x - 2y) \) from both the numerator and the denominator.
- Cancel \( (x + 2y) \) from both the numerator and the denominator.
This simplifies to:
\[
\frac{x - 10y}{3}
\]
### Final Answer
\[
\frac{x - 10y}{3}
\]
This simplified form is the final answer after dividing and simplifying the given rational expressions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe3ab2835-e63c-462d-897e-c9721400fd30%2Fdbe7fe9d-b8a9-4e04-ac3a-d27b78f8c4a8%2Fbrn3wy.png&w=3840&q=75)
Transcribed Image Text:### Dividing Rational Expressions Involving Multivariate Quadratics
#### Problem Statement
**Divide:**
\[
\frac{x^2 - 12xy + 20y^2}{x^2 - 4y^2} \div \frac{3x - 6y}{x + 2y}
\]
**Simplify** your answer as much as possible.
#### Explanation
To divide these rational expressions, follow these steps:
1. **Rewrite the division as a multiplication by the reciprocal:**
\[
\frac{x^2 - 12xy + 20y^2}{x^2 - 4y^2} \times \frac{x + 2y}{3x - 6y}
\]
2. **Factor all polynomials:**
- The numerator \(x^2 - 12xy + 20y^2\) can be factored as \((x - 2y)(x - 10y)\).
- The denominator \(x^2 - 4y^2\) is a difference of squares, which factors as \((x - 2y)(x + 2y)\).
- The numerator \(3x - 6y\) can be factored as \(3(x - 2y)\).
Therefore, we have:
\[
\frac{(x - 2y)(x - 10y)}{(x - 2y)(x + 2y)} \times \frac{x + 2y}{3(x - 2y)}
\]
3. **Cancel out common factors:**
- Cancel \( (x - 2y) \) from both the numerator and the denominator.
- Cancel \( (x + 2y) \) from both the numerator and the denominator.
This simplifies to:
\[
\frac{x - 10y}{3}
\]
### Final Answer
\[
\frac{x - 10y}{3}
\]
This simplified form is the final answer after dividing and simplifying the given rational expressions.
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