Divide numerator and denominator by the highest power of x in the denominator and proceed from there. Find the limits in Exercises 23–36. 8x² – 3 1/3 x² + 8x2 – 3 23. lim x→0 V 2x? + x 24. lim x--00 \5 x² – 5x 25. lim x→-ox2 + 7x 26. lim x→ o Vx + x – 2 2Vx + x! 2 + Vx 27. lim 28. lim x00 2 - Vx Зх — 7 Vx – Vĩ VI + Vĩ x' + x4 29. lim 30. lim x→-00 VI lim 32. x--0 2x + x²/3 – 4 2x/3 – x'/3 + 7 5x + 3 31. lim x-00 8/5 + 3x + Vx Vx² + 1 Vx² + 1 33. lim x00 x + 1 34. lim x→-0 x + 1 4 - 3x3 lim 35. lim x→∞ V4x? + 25 36. x→-0 Vx6 + 9

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Divide numerator and denominator by the highest power of x in the
denominator and proceed from there. Find the limits in Exercises 23–36.
8x² – 3
1/3
x² +
8x2 – 3
23. lim
x→0 V 2x? + x
24. lim
x--00
\5
x² – 5x
25. lim
x→-ox2 + 7x
26. lim
x→ o Vx + x – 2
2Vx + x!
2 + Vx
27. lim
28. lim
x00 2 - Vx
Зх — 7
Vx – Vĩ
VI + Vĩ
x' + x4
29. lim
30. lim
x→-00
VI
lim
32.
x--0 2x + x²/3 – 4
2x/3 – x'/3 + 7
5x + 3
31. lim
x-00 8/5 + 3x + Vx
Vx² + 1
Vx² + 1
33. lim
x00 x + 1
34. lim
x→-0 x + 1
4 - 3x3
lim
35. lim
x→∞ V4x? + 25
36.
x→-0 Vx6 + 9
Transcribed Image Text:Divide numerator and denominator by the highest power of x in the denominator and proceed from there. Find the limits in Exercises 23–36. 8x² – 3 1/3 x² + 8x2 – 3 23. lim x→0 V 2x? + x 24. lim x--00 \5 x² – 5x 25. lim x→-ox2 + 7x 26. lim x→ o Vx + x – 2 2Vx + x! 2 + Vx 27. lim 28. lim x00 2 - Vx Зх — 7 Vx – Vĩ VI + Vĩ x' + x4 29. lim 30. lim x→-00 VI lim 32. x--0 2x + x²/3 – 4 2x/3 – x'/3 + 7 5x + 3 31. lim x-00 8/5 + 3x + Vx Vx² + 1 Vx² + 1 33. lim x00 x + 1 34. lim x→-0 x + 1 4 - 3x3 lim 35. lim x→∞ V4x? + 25 36. x→-0 Vx6 + 9
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