distribution as an appre Test of p=0.93 vs p*0.93 Sample X N 1 2,158 1902 Sample p 0.881372 95% CI a. Is the test two-tailed, left-tailed, or right-tailed? Right tailed test O Two-tailed test O Left-tailed test b. What is the test statistic? on, and assume (0.867729,0.895014) -8.85 The test statistic is (Round to two decimal places as needed.) c. What is the P-value? Z-Value P-Value 0.000 The P-value is (Round to three decimal places as needed.) d. What is the null hypothesis and what do you condude about it? Identify the null hypothesis OA H₂:p>0.90 OB. H₂:p*0.93 OC. H₂ p<0.93 (e).
distribution as an appre Test of p=0.93 vs p*0.93 Sample X N 1 2,158 1902 Sample p 0.881372 95% CI a. Is the test two-tailed, left-tailed, or right-tailed? Right tailed test O Two-tailed test O Left-tailed test b. What is the test statistic? on, and assume (0.867729,0.895014) -8.85 The test statistic is (Round to two decimal places as needed.) c. What is the P-value? Z-Value P-Value 0.000 The P-value is (Round to three decimal places as needed.) d. What is the null hypothesis and what do you condude about it? Identify the null hypothesis OA H₂:p>0.90 OB. H₂:p*0.93 OC. H₂ p<0.93 (e).
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Transcribed Image Text:4
Q
4
71
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A poll of 2,158 randomly selected adults showed that 88% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal
distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p=0.93 vs p *0.93
Sample X
N
2,158
1
1902
S
a. Is the test two-tailed, left-tailed, or right-tailed?
O Right tailed test
O Two-tailed test
O Left-tailed test
b. What is the test statistic?
The test statistic is
(Round to two decimal places as needed.)
c. What is the P-value?
The P-value is
(Round to three decimal places as needed.)
d. What is the null hypothesis and what do you conclude about it?
Identify the null hypothesis.
OA Ho:p>0.93
OB. Ho: p*0.93
OC. Ho: p<0.93
OD. H.: n=193
X
command
H
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3
BO
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Sample p
0.881372
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с
4
95% CI
R
(0.867729,0.895014)
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5
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6
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Z-Value
-8.85
Y
H
9
P-Value
0.000
N
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Time Remaining: 01:07:08
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Transcribed Image Text:A poll of 2,158 randomly selected adults showed that 88% of them own cell phones. The technology display below results from a test of the claim that 93% of adults own cell phones. Use the normal
distribution as an approximation to the binomial distribution, and assume a 0.05 significance level to complete parts (a) through (e).
Test of p=0.93 vs p *0.93
Sample X
N
2,158
1
S
OA. Ho: p>0.93
OB. Ho: p*0.93
OC. Ho: p<0.93
OD. Ho: p=0.93
nd
1902
X
H
Choose the correct answer below.
OA. Reject the null hypothesis because the P-value is greater than the significance level, a
OB. Fail to reject the null hypothesis because the P-value is greater than the significance level, a
OC. Fail to reject the null hypothesis because the P-value is less than or equal to the significance level, a
OD. Reject the null hypothesis because the P-value is less than or equal to the significance level, a
e. What is the final conclusion?
L
Sample p
0.881372
OA. There is not sufficient evidence to support the claim that 93% of adults own a cell phone.
OB. There is sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone
OC. There is sufficient evidence to support the claim that 93% of adults own a cell phone
OD. There is not sufficient evidence to warrant rejection of the claim that 93% of adults own a cell phone
II
9
H
T TYLU
ZOEL
1
II
E
D
C
95% CI
Z-Value
(0.867729,0.895014) -8.85
R
F
N
P-Value
0.000
T
G
MacBook Air
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Time Remaining: 01:06:48
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