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- Low-fat or low-carb? Are low-fat diets or low-carb diets more effective for weight loss? A sample of 77 subjects went on a low-carbohydrate diet for six months. At the end of that time, the sample mean weight loss was 4.7 kilograms with a sample standard deviation of 7.16 kilograms. A second sample of 79 subjects went on a low-fat diet. Their sample mean weight loss was 2.6 kilograms with a standard deviation of 5.90 kilograms. Can you conclude that the mean weight loss differs between the two diets? Let 4, denote the mean weight lost on the low-carb diet and u, denote the mean weight lost on the low-fat diet. Use the a = 0.01 level and the TI-84 Plus calculator. Compute the -value. Round the answer to four decimal places. Determine whether to reject H0 State a conclusionWhere are the deer? Random samples of square-kilometer plots were taken in different ecological locations of a national park. The deer counts per square kilometer were recorded and are shown in the following table. Mountain Brush Sagebrush Grassland Pinon Juniper 35 17 2 30 53 6 20 19 2 26 19 8 Shall we reject or accept the claim that there is no difference in the mean number of deer per square kilometer in these different ecological locations? Use a 5% level of significance. (a) What is the level of significance? State the null and alternate hypotheses. Ho: μ1 = μ2 = μ3; H1: All three means are different.Ho: μ1 = μ2 = μ3; H1: Exactly two means are equal. Ho: μ1 = μ2 = μ3; H1: Not all the means are equal.Ho: μ1 = μ2 = μ3; H1: At least two means are equal. (b) Find SSTOT, SSBET, and SSW and check that SSTOT = SSBET + SSW. (Use 3 decimal places.) SSTOT = SSBET = SSW = Find d.f.BET, d.f.W, MSBET, and MSW. (Use 2 decimal places for MSBET, and MSW.)…The mean score on a driving exam for a group of driver’s education students is 76 points, with a standard deviation of 6 points. Apply chebychev’s theorem to the data using K=2. Interpret, At least ___% of the exam score falls between ___and ____
- please provide accurate answerWhich of the following gives a measure of how “spread out” or noisy a particular data set is? p-value validity effect size standard deviationChoose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
- Cost of Building a Home According to the National Association of Home Builders, the average cost of building a home in the Northeast is $117.91 per square foot. A random sample of 34 new homes indicated that the mean cost was $120.61and the standard deviation was $17. Can it be concluded that the mean cost differs from $117.91, using the 0.10level of significance? Use the P-value method. Use a graphing calculator. (b) Find the P-value. Round the answer to at least four decimal places. P-value=The number of peanuts in a 16 ounce can of nut munchies is normally distributed with a mean of 93.6 and a standard deviation of 4.2 peanuts the number of peanuts in a 20 ounce can of gone nuts is normally distributed with a mean of 111.8 and a standard deviation of 3.4 peanuts. (a) Carmen purchased a 16 ounce can of nut munchies and counted 100 peanuts what is the Z score for this can of peanuts? (b) Angelo purchased a 20 ounce can of gone nuts and counted 116 peanuts what is the Z score for this can of peanuts? (c) Carmen declares that purchase purchasing her can of nut munchies with 100 peanuts is less likely than Angelo purchasing a can of gone nuts with 116 peanuts is Carmen statement correct? Use the definition of a Z score to support or refute Carmen's claim.For a sample, a score that is 12 points above the mean has a z-score of z = 1.20. What is the sample standard deviation?
- Cost of Building a Home According to the National Association of Home Builders, the average cost of building a home in the Northeast is $117.91 per square foot. A random sample of 42 new homes indicated that the mean cost was $123.87 and the standard deviation was $15. Can it be concluded that the mean cost differs from $117.91, using the 0.05 level of significance? Use the P-value method. Use a graphing calculator. Find the P-value. Round the answer to at least four decimal places. P-value=Detecting gypsy moths The gypsy moth is a serious threat to oak and aspen trees. A state agriculture department places traps throughout the state to detect the moths. Each month, an SRS of 50 traps is inspected, the number of moths in each trap is recorded, and the mean number of moths is calculated. Based on years of data, the distribution of moth counts is discrete and strongly skewed with a mean of 0.5 and a standard deviation of 0.7. a. Explain why it is reasonable to use a Normal distribution to approximate the sampling distribution of for SRSS of size 50. b. Estimate the probability that the mean number of moths in a sample of size 50 is greater than or equal to 0.6. c. In a recent month, the mean number of moths in an SRS of size 50 was = 0.6. Based on this result, is there convincing evidence that the moth population is getting larger in this state? Explain your reasoning.Where are the deer? Random samples of square-kilometer plots were taken in different ecological locations of a national park. The deer counts per square kilometer were recorded and are shown in the following table. Mountain Brush Sagebrush Grassland Pinon Juniper 33 18 10 27 57 4 22 18 2 29 26 13 Shall we reject or accept the claim that there is no difference in the mean number of deer per square kilometer in these different ecological locations? Use a 5% level of significance. (b) Find SSTOT, SSBET, and SSW and check that SSTOT = SSBET + SSW. (Use 3 decimal places.) SSTOT = SSBET = SSW = Find d.f.BET, d.f.W, MSBET, and MSW. (Use 2 decimal places for MSBET, and MSW.) dfBET = dfW = MSBET = MSW = Find the value of the sample F statistic. (Use 3 decimal places.)What are the degrees of freedom? (numerator) (denominator) Make a summary table for your ANOVA test. Source ofVariation Sum ofSquares Degrees ofFreedom MS…