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Distillate Component Ibmol/h iC4 пC4 iC5 пCs (12) 442 13 Feed Debutanizer Component Ibmol/h iC4 nCa (LK) ic5 (HK) (1) (468) 12 448 36 15 23 39.1 272.2 31.0 Св 876.3 Bottoms Component Ibmol/h 6 23 nC4 iC5 nC5 C6 (14) (23) (39.1) (272.2) (31.0) (408.3) Cg C9 10 80 psla 1.0 к, 0.1 0.01 0.1 10 Kcs ПT 1. ПL

Distillate Component Ibmol/h iC4 пC4 iC5 пCs (12) 442 13 Feed Debutanizer Component Ibmol/h iC4 nCa (LK) ic5 (HK) (1) (468) 12 448 36 15 23 39.1 272.2 31.0 Св 876.3 Bottoms Component Ibmol/h 6 23 nC4 iC5 nC5 C6 (14) (23) (39.1) (272.2) (31.0) (408.3) Cg C9 10 80 psla 1.0 к, 0.1 0.01 0.1 10 Kcs ПT 1. ПL

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Estimate the product distributions for nonkey components by the Fenske equation for the debutanizer shown in Figure  and considered  estimate the Nmin by the Fenske equation. Assume a uniform operating pressure of 80 psia (552 kPa) throughout and utilize the ideal K-values given by Bachelor [4] as plotted in Figure. 

Distillate Component Ibmol/h iC4 пC4 iC5 пCs (12) 442 13 Feed Debutanizer Component Ibmol/h iC4 nCa (LK) ic5 (HK) (1) (468) 12 448 36 15 23 39.1 272.2 31.0 Св 876.3 Bottoms Component Ibmol/h 6 23 nC4 iC5 nC5 C6 (14) (23) (39.1) (272.2) (31.0) (408.3) Cg C9
Transcribed Image Text:Distillate Component Ibmol/h iC4 пC4 iC5 пCs (12) 442 13 Feed Debutanizer Component Ibmol/h iC4 nCa (LK) ic5 (HK) (1) (468) 12 448 36 15 23 39.1 272.2 31.0 Св 876.3 Bottoms Component Ibmol/h 6 23 nC4 iC5 nC5 C6 (14) (23) (39.1) (272.2) (31.0) (408.3) Cg C9
10 80 psla 1.0 к, 0.1 0.01 0.1 10 Kcs ПT 1. ПL
Transcribed Image Text:10 80 psla 1.0 к, 0.1 0.01 0.1 10 Kcs ПT 1. ПL
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