Distance of a planet from the earth is 2.5 × 107 m. If mass of planet is same as that of the earth, calculate the force of gravitation between then (mass of earth = 5.98 x 10²4 kg, G = 6.67 x 10-¹¹ Nm²/kg²)
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- Determine the ratio of Earth's gravitational force exerted on an 80-kg person when at Earth's surface and when 1100 km above Earth's surface. The radius of Earth is 6370 km. FE on P,surface FE on Ph 195] ΑΣΦ ?Taking the age of Earth to be about 4 ✕ 109 years and assuming its orbital radius of 1.5 ✕ 1011 m has not changed and is circular, calculate the approximate total distance Earth has traveled since its birth (in a frame of reference stationary with respect to the Sun).When a falling meteoroid is at a distance above the Earth's surface of 2.4 times the Earth's radius, what is its acceleration due to the Earth's gravitation? (Units: m/s2)
- A satellite m = 500 kg orbits the earth at a distance d = 225km above the of the planetThe radius of the earth r_{e} = 638 * 10 ^ 6 * m and the gravitational constant G = 6.67 * 10 ^ - 11 * N * m ^ 2 / k * g ^ 2 and the Earth's mass m_{e} = 5.98 * 10 ^ 24 * kg What the speed of the satellite in m/sAstronomical observations of our Milky Way galaxy indicate that it has a mass of about 8 x 10¹¹ solar masses. A star orbiting near the galaxy's periphery is 5.9 x 104 light years from its center. (For your calculations, assume that the galaxy's mass is concentrated near its center.) What should the orbital period of that star be? yr If its period is 5.8 x 107 years instead, what is the mass of the galaxy? Such calculations are used to imply the existence of "dark matter" in the universe and have indicated, for example, the existence of very massive black holes at the centers of some galaxies. solar massesYour weight on Earth is W0W0. Let mE≡mE≡ mass of the Earth; RE≡RE≡ radius of the Earth. What would your weight be if you were on a planet with a mass of 3mE3mE and radius of 4RE4RE?
- When a falling meteoroid is at a distance above the Earth's surface of 3.10 times the Earth's radius, what is its acceleration due to the Earth's gravitation? m/s? towards earthUse Newton’s universal gravitation formula to determine the gravitational force of attraction between the earth and the moon given: mass (moon) m(moon)=7.35 x 10^22kg the mass of the earth is m(earth)=5.98 x 10^24kg the distance between centers of the earth and moon is r=3.92 x 10^8 m use Newton gravitation equation F=G(m(1) x m(2))/r^2Astronomical observations of our Milky Way galaxy indicate that it has a mass of about 8 x 1011 solar masses. A star orbiting near the galaxy's periphery is 5.6 x 104 light years from its center. (For your calculations, assume that the galaxy's mass is concentrated near its center.) (a) What should the orbital period of that star be? yr (b) If its period is 5.1 x 107 years instead, what is the mass of the galaxy? Such calculations are used to imply the existence of "dark matter" in the universe and have indicated, for example, the existence of very massive black holes at the centers of some galaxies. solar masses
- 3. The gravitational acceleration at Earth's surface (ge) is about 10 m/s? and ge = GM/R?. What is gp at the surface of a planet with 2X Earth's mass and 3X Earth's radius?11 Astronomical observations of our Milky Way galaxy indicate that it has a mass of about 8.0 x 10- solar masses. A star orbiting near the galaxy's periphery is 5.9 x 10" light-years from its center. (a) What should the orbital period (in y) of that star be? y. (b) If its period is 6.1 x 10' years instead, what is the mass (in solar masses) of the galaxy? Such calculations are used to imply the existence of other matter, such as a very massive black hole at the center of the Milky Way. solar masses