disp(" f(x) = 4x4 - 32x3 + 89x2 - 103x + 42 = 0 "); disp(" find the root between 0 and 1.2 "); disp(" ---------------------------------------- "); a=0; b=1.2; for i=1:10 c=(a+b)/2; fa = 4*a^4 - 32*a^3 + 89*a^2 - 103*a + 42; fc = 4*c^4 - 32*c^3 + 89*c^2 - 103*c + 42; if fa*fc < 0 a = a; b = c; else a = c; b = b; end; if fa*fc == 0 fprintf(" root is found \n"); end; fprintf(" root is %2.4f \n", c); end; (can you do it with c++)
disp(" f(x) = 4x4 - 32x3 + 89x2 - 103x + 42 = 0 "); disp(" find the root between 0 and 1.2 "); disp(" ---------------------------------------- "); a=0; b=1.2; for i=1:10 c=(a+b)/2; fa = 4*a^4 - 32*a^3 + 89*a^2 - 103*a + 42; fc = 4*c^4 - 32*c^3 + 89*c^2 - 103*c + 42; if fa*fc < 0 a = a; b = c; else a = c; b = b; end; if fa*fc == 0 fprintf(" root is found \n"); end; fprintf(" root is %2.4f \n", c); end; (can you do it with c++)
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
disp(" f(x) = 4x4 - 32x3 + 89x2 - 103x + 42 = 0 ");
disp(" find the root between 0 and 1.2 ");
disp(" ---------------------------------------- ");
a=0;
b=1.2;
for i=1:10
c=(a+b)/2;
fa = 4*a^4 - 32*a^3 + 89*a^2 - 103*a + 42;
fc = 4*c^4 - 32*c^3 + 89*c^2 - 103*c + 42;
if fa*fc < 0
a = a;
b = c;
else
a = c;
b = b;
end;
if fa*fc == 0
fprintf(" root is found \n");
end;
fprintf(" root is %2.4f \n", c);
end;
(can you do it with c++)
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