Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 118 disks are summarized as follows: Shock Resistance High Low Scratch High 54 13 Resistance Low 12 39 Let A denote the event that a disk has high shock resistance, and let B denote the event that a disk has high scratch resistance. If a disk is selected at random, determine the following probabilities. Round your answers to two decimal places (e.g. 98.76). (a) P(A) = i (b) P(B) = 1 (c) P(A) = ₁ (d) P(ANB) = (e) P(AUB) = (f) P(A'U B) = i i

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
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### Analysis of Scratch and Shock Resistance of Polycarbonate Disks

Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 118 disks are summarized as follows:

---

|                  | Shock Resistance |
|----------------|-------------------------|
|                  | High       | Low       |
|----------------|------------|------------|
| Scratch High  | 54            | 13          |
| Scratch Low   | 12            | 39          |
---

Let \(A\) denote the event that a disk has high shock resistance, and let \(B\) denote the event that a disk has high scratch resistance. If a disk is selected at random, determine the following probabilities. Round your answers to two decimal places (e.g., 98.76).

---

- \(\mathbf{(a)\ P(A) =}\) 
- \(\mathbf{(b)\ P(B) =}\)
- \(\mathbf{(c)\ P(A') =}\)
- \(\mathbf{(d)\ P(A \cap B) =}\)
- \(\mathbf{(e)\ P(A \cup B) =}\)
- \(\mathbf{(f)\ P(A' \cup B') =}\)

---

The table above summarizes the disk counts based on their scratch and shock resistance classifications. The calculations will involve using the total counts and specific counts to determine the mentioned probabilities.
Transcribed Image Text:### Analysis of Scratch and Shock Resistance of Polycarbonate Disks Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 118 disks are summarized as follows: --- | | Shock Resistance | |----------------|-------------------------| | | High | Low | |----------------|------------|------------| | Scratch High | 54 | 13 | | Scratch Low | 12 | 39 | --- Let \(A\) denote the event that a disk has high shock resistance, and let \(B\) denote the event that a disk has high scratch resistance. If a disk is selected at random, determine the following probabilities. Round your answers to two decimal places (e.g., 98.76). --- - \(\mathbf{(a)\ P(A) =}\) - \(\mathbf{(b)\ P(B) =}\) - \(\mathbf{(c)\ P(A') =}\) - \(\mathbf{(d)\ P(A \cap B) =}\) - \(\mathbf{(e)\ P(A \cup B) =}\) - \(\mathbf{(f)\ P(A' \cup B') =}\) --- The table above summarizes the disk counts based on their scratch and shock resistance classifications. The calculations will involve using the total counts and specific counts to determine the mentioned probabilities.
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