Disk A and B have a mass of 4 kg and 6 kg, respectively. If they are sliding on a smooth horizontal plane with the velocities shown, determine their speeds just after impact. coefficient of restitution between them is e =0.8. Your solution must include the following: (a) tangential component of the velocities after impact for both disks, (Vat)2 and (Vgt)2, (b) normal component of the velocities after impact for both disks, (Van)2 and (VBn)2, (c) the velocities after impact for both disks, (VA)2 and (vg)2, [4] (a) (VẠL)2 Og = 5 m/s e = 0.8 The 45° %3D m, = 4 kg 30 me = 6 kg B =3 m/s %3D (VBr)2 = [17] (b) (VAn)2 = (VBn)2 [4] (c) (Va)2 (VB)2 =

Disk A and B have a mass of 4 kg and 6 kg, respectively. If they are sliding on a smooth horizontal plane with the velocities shown, determine their speeds just after impact. coefficient of restitution between them is e =0.8. Your solution must include the following: (a) tangential component of the velocities after impact for both disks, (Vat)2 and (Vgt)2, (b) normal component of the velocities after impact for both disks, (Van)2 and (VBn)2, (c) the velocities after impact for both disks, (VA)2 and (vg)2, [4] (a) (VẠL)2 Og = 5 m/s e = 0.8 The 45° %3D m, = 4 kg 30 me = 6 kg B =3 m/s %3D (VBr)2 = [17] (b) (VAn)2 = (VBn)2 [4] (c) (Va)2 (VB)2 =

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

Disk A and B have a mass of 4 kg and 6 kg,
respectively. If they are sliding on a smooth
horizontal plane with the velocities shown,
determine their speeds just after impact.
coefficient of restitution between them is e =0.8.
=5 m/s
e 0,8
The
45°
m, = 4 kg
Your solution must include the following:
(a) tangential component of the velocities after
impact for both disks, (VAt)2 and (Vet)2,
(b) normal component of the velocities after impact =3 m/s
for both disks, (VAn)2 and (VBn)2,
(c) the velocities after impact for both disks, (vA)2 and (vB)2,
30
ma = 6 kg
[4] (a) (VAt)2 =
(VBt)2
[17] (b) (Van)2 =
(VBn) 2
[4] (c) (VA)2
(VB)2 =
%3D
%3D
%3D

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