Discussion 3 The function k(x) = In Vx² +3 (Equation 1) is the composition of the three functions f(x) = In x, g(x) = /x , and h(x) =x² +3. Therefore, k(x) = (f og• h)(x) = f(g(h(x))) = In Vx² +3. %3D dk а) Find by taking the derivative of Equation 1 by using quick methods. dx Now, find the derivative by using the chain rule in Liebniz notation. Does this agree with the derivative found in part (a)? b) dk _ df dg dh dx dg dh dx Chain rule in Liebniz notation: h(x) = x² +3 Hint: g(h) = h f(g) = In g

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Discussion 3
The function
k(x) = In Vx2 +3
(Equation 1)
is the composition of the three functions f(x) = In x, g(x) = Vx , and h(x) = x² +3. Therefore,
2
k(x) = (f °goh)(x) = f(g(h(x))) = In vx2 +3.
dk
by taking the derivative of Equation 1 by using quick methods.
dx
а)
Find
b)
Now, find the derivative by using the chain rule in Liebniz notation. Does this agree with
the derivative found in part (a)?
dk
Chain rule in Liebniz notation:
dx
df dg dh
dg dh dx
h(x) = x² +3
= x +3
Hint:
g(h) = /h
f(g) = In g
Transcribed Image Text:Discussion 3 The function k(x) = In Vx2 +3 (Equation 1) is the composition of the three functions f(x) = In x, g(x) = Vx , and h(x) = x² +3. Therefore, 2 k(x) = (f °goh)(x) = f(g(h(x))) = In vx2 +3. dk by taking the derivative of Equation 1 by using quick methods. dx а) Find b) Now, find the derivative by using the chain rule in Liebniz notation. Does this agree with the derivative found in part (a)? dk Chain rule in Liebniz notation: dx df dg dh dg dh dx h(x) = x² +3 = x +3 Hint: g(h) = /h f(g) = In g
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