Discuss why the Effective Length, L’, of an acoustic element (e.g. the neck of a Helmholtz resonator) is always longer than its physical length.
Discuss why the Effective Length, L’, of an acoustic element (e.g. the neck of a Helmholtz resonator) is always longer than its physical length.
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![Discuss why the Effective Length, L', of an acoustic element (e.g. the neck of a
Helmholtz resonator) is always longer than its physical length.
Calculate the resonant frequency of a Helmholtz resonator that has a neck with
a circular opening of radius, a = 1.7 cm, an Inertance, M = 80 kg/m², and a
spring constant due to its enclosed volume, s = 1800 N/m.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc8545c89-19c2-4d90-bc33-b5c0e87e8b3c%2F31d2c1e0-d424-489a-b3a9-3a9bd2e63a5e%2Ff6i0q5o_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Discuss why the Effective Length, L', of an acoustic element (e.g. the neck of a
Helmholtz resonator) is always longer than its physical length.
Calculate the resonant frequency of a Helmholtz resonator that has a neck with
a circular opening of radius, a = 1.7 cm, an Inertance, M = 80 kg/m², and a
spring constant due to its enclosed volume, s = 1800 N/m.
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