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Discuss the possibilities for the roots to : 2x'-5x - 6x+4 = 0 12. 3x - 5x -x² -8x+4 =0

Discuss the possibilities for the roots to : 2x'-5x - 6x+4 = 0 12. 3x - 5x -x² -8x+4 =0

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.6: Solving Quadratic Equations By Using The Quadratic Formula
Problem 50PPS
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Conjugate Pairs Theorem - P(x)= 0 is a polynomial equation with real coefficients and the complex number a+bi (b0) is a root, then a-bi is also a root. 10. Create a polynomial equation with real coefficients that has 2 and 1-i as roots. Descartes's Rule of Signs - Suppose P(x)=0 is a polynomial equation with real coefficients and with terms written in descending order. The number of positive real roots of the equation is either equal to the number of variations of sign of P(x) or less than that by an even number. The number of negative real roots of the equation is either equal to the number of variations of sign of P(-x) or less than that by an even number Discuss the possibilities for the roots to : 2x - 5x² – 6x+4 = 0 12.3x*-5x' -x² - 8x+4=0 |
Transcribed Image Text:Conjugate Pairs Theorem - P(x)= 0 is a polynomial equation with real coefficients and the complex number a+bi (b0) is a root, then a-bi is also a root. 10. Create a polynomial equation with real coefficients that has 2 and 1-i as roots. Descartes's Rule of Signs - Suppose P(x)=0 is a polynomial equation with real coefficients and with terms written in descending order. The number of positive real roots of the equation is either equal to the number of variations of sign of P(x) or less than that by an even number. The number of negative real roots of the equation is either equal to the number of variations of sign of P(-x) or less than that by an even number Discuss the possibilities for the roots to : 2x - 5x² – 6x+4 = 0 12.3x*-5x' -x² - 8x+4=0 |
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