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Discuss the continuity of the function on the closed interval. Function Interval 8 – x, f(x) = [-3, 5] 8 + 2 x > 0 O The function is discontinuous because all piecewise functions are discontinuous at their domain boundaries. The function is continuous because Ilim f(x) and lim f(x) both exist. メー-3 メ-5 The function is continuous because the domain boundary is not inside the interval [-3, 5]. The function is continuous because lim f(x) = lim f(x) = f(0) = 8. メー0 メー0* O The function is discontinuous because f(-3) f(5).

Discuss the continuity of the function on the closed interval. Function Interval 8 – x, f(x) = [-3, 5] 8 + 2 x > 0 O The function is discontinuous because all piecewise functions are discontinuous at their domain boundaries. The function is continuous because Ilim f(x) and lim f(x) both exist. メー-3 メ-5 The function is continuous because the domain boundary is not inside the interval [-3, 5]. The function is continuous because lim f(x) = lim f(x) = f(0) = 8. メー0 メー0* O The function is discontinuous because f(-3) f(5).

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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if yo Ass You 6. DETAILS LARCALC11 1.4.037. Discuss the continuity of the function on the closed interval. Function Interval 8 – x, メe o f(x) = < [-3, 5] 1 8 + 2 x > 0 The function is discontinuous because all piecewise functions are discontinuous at their domain boundaries. The function is continuous because lim f(x) and lim f(x) both exist. X→-3 O The function is continuous because the domain boundary is not inside the interval [-3, 5]. O The function is continuous because lim f(x) = lim f(x) = f(0) = 8. メー0+ O The function is discontinuous because f(-3) = f(5). Submit Answer View Previous Question Question 6 of 10 View Next Que
Transcribed Image Text:if yo Ass You 6. DETAILS LARCALC11 1.4.037. Discuss the continuity of the function on the closed interval. Function Interval 8 – x, メe o f(x) = < [-3, 5] 1 8 + 2 x > 0 The function is discontinuous because all piecewise functions are discontinuous at their domain boundaries. The function is continuous because lim f(x) and lim f(x) both exist. X→-3 O The function is continuous because the domain boundary is not inside the interval [-3, 5]. O The function is continuous because lim f(x) = lim f(x) = f(0) = 8. メー0+ O The function is discontinuous because f(-3) = f(5). Submit Answer View Previous Question Question 6 of 10 View Next Que
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