Directions: Find the equations given the derivatives. Encircle the letter of your answer. 1. Which of the illustrative equations that will give a derivative of 10? А. у %3D 10х -20 C. y 2x5- 10 В. у %3D х10 — 5 D. y= 5x2 -5 2. Which of the illustrative equations that will give a derivative of 2x-10? A. y = 2x2 - 10x С. у %3Dх2- 10х В. у %3D х2 + 10х D. y %3D 10х - 2х2 3. Which of the illustrative equations that will give a slope 10 of the tangent line
Directions: Find the equations given the derivatives. Encircle the letter of your answer. 1. Which of the illustrative equations that will give a derivative of 10? А. у %3D 10х -20 C. y 2x5- 10 В. у %3D х10 — 5 D. y= 5x2 -5 2. Which of the illustrative equations that will give a derivative of 2x-10? A. y = 2x2 - 10x С. у %3Dх2- 10х В. у %3D х2 + 10х D. y %3D 10х - 2х2 3. Which of the illustrative equations that will give a slope 10 of the tangent line
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Please answer 4 & 5 thank you
Transcribed Image Text:Directions: Find the equations given the derivatives. Encircle the letter of your
answer.
1. Which of the illustrative equations that will give a derivative of 10?
А. у %3D 10х - 20
C. y = 2x5- 10
%3D
B. y = x10 – 5
D. y= 5x2 - 5
2. Which of the illustrative equations that will give a derivative of 2x - 10?
A. y = 2x2 – 10x
С. у %3D х2-10х
В. у %3D х2 + 10х
D. y = 10x - 2x2
%3D
3. Which of the illustrative equations that will give a slope 10 of the tangent line
to its graph?
A. y = 2x2-2x at(2,3)
С.у %3D Зx2-2х at(1,3)
B. y= 2x2 +2x at(2,3)
D. y = 3x2 + 2x at(1,3)
%3D
4. Which of the illustrative equations that will give a slope 5 of the tangent line to
its graph?
А. у %3D 4x2 - 5х at (3, 1)
С. у %3D 2x2 - 2х at (3,1)
В. у %3D 3x2- 5х at (3,1)
D. y %3D x2- х at (3, 1)
5. Which of the illustrative equations that will give a slope 3 of the tangent line to
its graph?
A. y = 4x2 - 5x at (1,2)
C. y = 5x2 -6x at (1,2)
%3D
В. у32x2-3х at (1,2)
D. y = 3x² – 4x at (1,2)
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