Directions: Find each missing length. Give all answ 1. 2. A 14 196 +100 10 x=2√574 √29642 2√10 3. X 45° 90 2 UTO=x√5/₂2 y=2 x=2 X 4. 16 18 √580=c² 25k/5 30° 14√3 18+16²=(² 324+266=530 14√√3=x√3 √3 55 x = 1 y=x√3

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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I need help with knowing how to find missing side lengths and measures. Are any of these right if not what did I do wrong?
5.
Name:
Date:
Bell:
** This is a 2-page document! **
Directions: Find each missing length. Give all answers in simplest radical form.
1.
2.
14+10²= 6²
16
18
196 +100
x=2√574
√580=1²
25k/5
C
2√10
y
cos
an 0 =
14
3.
sin 0 =
■
y
x
12
10
2x = 300
x
30
2
x=15
60°
x = 2x
y=15
y
7. Find the values of the six trigonometric
functions for 0.
75
12² +5² = (²
5
144 +25=(²
√169=C²
13
13
12
تر است
13
5
13
45°
90
√296122
2 UTO=x√2/2
y=2
x=2
csc 0 =
sec 0 =
cot 0 =
5
نادم
Unit 12: Trigonometry
Homework 1: Pythagorean Theorem, Special
Right Triangles, & Trig Functions
18+16²=(²
324+256=530
14√3=x√3
√3
√5
X = H
y=x√3
X
4.
6.
30°
X
14√3
45°
16=x√3
16
x=
192
8. Find the values of the six trigonometric
functions for 0.
16
2
12².
** = 16₂
0
IN.XAj00
csc 0 =
sec 0 w
cot 0 =
S
12
sin 0 =
cos 0 =
tan 0 =>
y
20
16
20
12
20
14
2
tor
20
16
20
12
Transcribed Image Text:5. Name: Date: Bell: ** This is a 2-page document! ** Directions: Find each missing length. Give all answers in simplest radical form. 1. 2. 14+10²= 6² 16 18 196 +100 x=2√574 √580=1² 25k/5 C 2√10 y cos an 0 = 14 3. sin 0 = ■ y x 12 10 2x = 300 x 30 2 x=15 60° x = 2x y=15 y 7. Find the values of the six trigonometric functions for 0. 75 12² +5² = (² 5 144 +25=(² √169=C² 13 13 12 تر است 13 5 13 45° 90 √296122 2 UTO=x√2/2 y=2 x=2 csc 0 = sec 0 = cot 0 = 5 نادم Unit 12: Trigonometry Homework 1: Pythagorean Theorem, Special Right Triangles, & Trig Functions 18+16²=(² 324+256=530 14√3=x√3 √3 √5 X = H y=x√3 X 4. 6. 30° X 14√3 45° 16=x√3 16 x= 192 8. Find the values of the six trigonometric functions for 0. 16 2 12². ** = 16₂ 0 IN.XAj00 csc 0 = sec 0 w cot 0 = S 12 sin 0 = cos 0 = tan 0 => y 20 16 20 12 20 14 2 tor 20 16 20 12
the nearest lanth.
12
9. Given the ratio for tan , find the remaining
ratios.
25+14
√41
J
CSC 8 =
VIT
52
sec 8 =
tan =
cot 0 =
5
tan 0 =
Directions: Give the exact ratios for each function below.
11. sin 45°
1 √2
12. tan 60°
15. sec 45°
sin 8 =
cos 8 =
NIS
14. cot 60°
SE
后
√3 Co+=
1
- اک
√41
Vai
5
175
√2
10. Given the ratio for csc 0, find the remaining
ratios.
7
2
51
sin =
cos 0 =
//
NCHINI
m/45
X 1 京
AVS J3
√3
3
Sec-3
SHyp
csc =
sec 0 =
cot 0 =
13. cos 30°
16. csc 60°
17
/m/A/N
3/2
Ta
اسکالر
CSC AJ
SHYP
pate:
Direc
1.
Transcribed Image Text:the nearest lanth. 12 9. Given the ratio for tan , find the remaining ratios. 25+14 √41 J CSC 8 = VIT 52 sec 8 = tan = cot 0 = 5 tan 0 = Directions: Give the exact ratios for each function below. 11. sin 45° 1 √2 12. tan 60° 15. sec 45° sin 8 = cos 8 = NIS 14. cot 60° SE 后 √3 Co+= 1 - اک √41 Vai 5 175 √2 10. Given the ratio for csc 0, find the remaining ratios. 7 2 51 sin = cos 0 = // NCHINI m/45 X 1 京 AVS J3 √3 3 Sec-3 SHyp csc = sec 0 = cot 0 = 13. cos 30° 16. csc 60° 17 /m/A/N 3/2 Ta اسکالر CSC AJ SHYP pate: Direc 1.
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