Dinitrogen tetroxide, N2O4, dissociates at room temperature to give nitrogen dioxide, NO2. N2O4 (g) ⇌ 2 NO2 (g) (a) The equilibrium constant Kc at 25°C is 0,125. What percentage of dinitrogen tetroxide is dissociated when 0,0300 mol N2O4 is placed in a 1,00 dm3 flask and left to reach equilibrium?

Chemistry & Chemical Reactivity
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Chapter15: Principles Of Chemical Reactivity: Equilibria
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Problem 3PS: Kc = 5.6 1012 at 500 K for the dissociation of iodine molecules to iodine atoms. I2(g) 2 I(g) A...
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Dinitrogen tetroxide, N2O4, dissociates at room temperature to give nitrogen dioxide, NO2.
N2O4 (g) ⇌ 2 NO2 (g)


(a) The equilibrium constant Kc at 25°C is 0,125. What percentage of dinitrogen tetroxide
is dissociated when 0,0300 mol N2O4 is placed in a 1,00 dm3 flask and left to reach
equilibrium?

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