Dinitrogen tetraoxide and nitrogen dioxide are two gases that exist in equilibrium at a range of temperatures. NO2 is a reddish brown gas while N2O4 is colorless. At high temperatures the red color is strong. At low temperatures the gas has less color. If we represent the equilibrium as, N2O4(g) We can conclude that the reaction is 2 NO2(g) 2 NO2(g) N₂O(g) Brown gas Colorless gas Cannana laminaMama Ca Exothermic Endothermic Neutral More information is needed to answer this question
Dinitrogen tetraoxide and nitrogen dioxide are two gases that exist in equilibrium at a range of temperatures. NO2 is a reddish brown gas while N2O4 is colorless. At high temperatures the red color is strong. At low temperatures the gas has less color. If we represent the equilibrium as, N2O4(g) We can conclude that the reaction is 2 NO2(g) 2 NO2(g) N₂O(g) Brown gas Colorless gas Cannana laminaMama Ca Exothermic Endothermic Neutral More information is needed to answer this question
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter12: Gaseous Chemical Equilibrium
Section: Chapter Questions
Problem 74QAP: The figures below represent the following reaction at equilibrium at different temperatures....
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Question
![Dinitrogen tetraoxide and nitrogen dioxide are two gases that exist in equilibrium at
a range of temperatures. NO2 is a reddish brown gas while N2O4 is colorless. At
high temperatures the red color is strong. At low temperatures the gas has less color.
If we represent the equilibrium as, N2O4(g)
We can conclude that the reaction is
2 NO2(g)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fffc14f3f-7dab-40ef-86e3-dda879a5d551%2Ffdc84c2f-fefa-4788-91db-abe2a0047b76%2Foltkkpm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Dinitrogen tetraoxide and nitrogen dioxide are two gases that exist in equilibrium at
a range of temperatures. NO2 is a reddish brown gas while N2O4 is colorless. At
high temperatures the red color is strong. At low temperatures the gas has less color.
If we represent the equilibrium as, N2O4(g)
We can conclude that the reaction is
2 NO2(g)
![2 NO2(g) N₂O(g)
Brown gas
Colorless gas
Cannana laminaMama Ca
Exothermic
Endothermic
Neutral
More information is needed to answer this question](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fffc14f3f-7dab-40ef-86e3-dda879a5d551%2Ffdc84c2f-fefa-4788-91db-abe2a0047b76%2F471x1at_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2 NO2(g) N₂O(g)
Brown gas
Colorless gas
Cannana laminaMama Ca
Exothermic
Endothermic
Neutral
More information is needed to answer this question
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