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Differentiate. f(x) = (3x – 4)(x + 4) ,1/2_Av-1/2 4x + 12 O A. f'(x) = 2.00x В. f (x) 3D4.5х 1/2 Oy - 1/2 2x + 12 OC. f(x) = 2.00x" 1/2 - 1/2 2х + 12 1/2 - 1/2 O D. f'(x) = 4.5x'/2 -. 4x + 12

Differentiate. f(x) = (3x – 4)(x + 4) ,1/2_Av-1/2 4x + 12 O A. f'(x) = 2.00x В. f (x) 3D4.5х 1/2 Oy - 1/2 2x + 12 OC. f(x) = 2.00x" 1/2 - 1/2 2х + 12 1/2 - 1/2 O D. f'(x) = 4.5x'/2 -. 4x + 12

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Differentiate. f(x) = (3x – 4)(/x +4) O A. f'(x) = 2.00x' 1/2 _Av-1/2 + 12 - 4x B. f'(x) = 4.5x' 1/2 2х - 2x-1/2 + 12 O C. f(x) = 2.00x"/2 - 2x-1/2 + 12 O D. f'(x) = 4.5x'/2 - 4x-1/2 + 12
Transcribed Image Text:Differentiate. f(x) = (3x – 4)(/x +4) O A. f'(x) = 2.00x' 1/2 _Av-1/2 + 12 - 4x B. f'(x) = 4.5x' 1/2 2х - 2x-1/2 + 12 O C. f(x) = 2.00x"/2 - 2x-1/2 + 12 O D. f'(x) = 4.5x'/2 - 4x-1/2 + 12
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f\left(x\right)=\left(3x-4\right)\left(\sqrt{x}+4\right)

f\left(x\right)= 3x\left(\sqrt{x}+4\right)-4\left(\sqrt{x}+4\right)

f\left(x\right)= 3x\sqrt{x}+12x-4\sqrt{x}-16

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