Differentiate y = Σ (k + 4)ak+8. k=0 y=Σ k=0

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Question

Thank you very much

### Problem Statement:

Differentiate the function defined by the following infinite series:

\[ y = \sum_{k=0}^{\infty} (k + 4)x^{k+8}. \]

### Solution:

Compute the derivative \( y' \) of the given function. The general form of the series should be maintained in the derivative.

\[ y' = \sum_{k=0}^{\infty} \frac{d}{dx} \left( (k+4)x^{k+8} \right). \]

### Steps to Differentiate:

1. **Identify the term to differentiate**:
   The term in the series to differentiate is \( (k+4)x^{k+8} \).

2. **Apply the power rule for differentiation**:
   \[\frac{d}{dx}(x^n) = n \cdot x^{n-1}.\]

3. **Differentiate the term in the context of the series**:
   \[ \frac{d}{dx}\left((k+4)x^{k+8}\right) = (k+4) \cdot (k+8)x^{k+8-1} = (k+4) \cdot (k+8)x^{k+7}. \]

4. **Express the differentiated term back into the series form**:
   \[ y' = \sum_{k=0}^{\infty} (k + 4)(k + 8)x^{k+7}. \]

Therefore, the derivative of the given function is:

\[ y' = \sum_{k=0}^{\infty} (k + 4)(k + 8)x^{k+7}. \]

### Explanation of Symbols:

- \(\sum\) (Sigma) represents the summation over an infinite series starting from \( k = 0 \).
- \( k \) is the index of summation.
- \( x \) is the variable with respect to which differentiation is performed.
- \( k + 4 \) and \( k + 8 \) are constants with respect to \( x \) within each term of the series.
  
This completes the differentiation of the infinite series \( y \).
Transcribed Image Text:### Problem Statement: Differentiate the function defined by the following infinite series: \[ y = \sum_{k=0}^{\infty} (k + 4)x^{k+8}. \] ### Solution: Compute the derivative \( y' \) of the given function. The general form of the series should be maintained in the derivative. \[ y' = \sum_{k=0}^{\infty} \frac{d}{dx} \left( (k+4)x^{k+8} \right). \] ### Steps to Differentiate: 1. **Identify the term to differentiate**: The term in the series to differentiate is \( (k+4)x^{k+8} \). 2. **Apply the power rule for differentiation**: \[\frac{d}{dx}(x^n) = n \cdot x^{n-1}.\] 3. **Differentiate the term in the context of the series**: \[ \frac{d}{dx}\left((k+4)x^{k+8}\right) = (k+4) \cdot (k+8)x^{k+8-1} = (k+4) \cdot (k+8)x^{k+7}. \] 4. **Express the differentiated term back into the series form**: \[ y' = \sum_{k=0}^{\infty} (k + 4)(k + 8)x^{k+7}. \] Therefore, the derivative of the given function is: \[ y' = \sum_{k=0}^{\infty} (k + 4)(k + 8)x^{k+7}. \] ### Explanation of Symbols: - \(\sum\) (Sigma) represents the summation over an infinite series starting from \( k = 0 \). - \( k \) is the index of summation. - \( x \) is the variable with respect to which differentiation is performed. - \( k + 4 \) and \( k + 8 \) are constants with respect to \( x \) within each term of the series. This completes the differentiation of the infinite series \( y \).
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

Blurred answer
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning